We know that
the equation of the parabola is of the form
y=ax²+bx+c
in this problem
y=1/4x²−x+3
where
a=1/4
b=-1
c=3
the coordinates of the focus are
(-b/2a,(1-D)/4a)
where D is the discriminant b²-4ac
D=(-1)²-4*(1/4)*3-----> D=1-3---> D=-2
therefore
x coordinate of the focus
-b/2a----> 1/[2*(-1/4)]----> 2

y coordinate of the focus
(1-D)/4a------> (1+2)/(4/4)---> 3

the coordinates of the focus are (2,3)

3 0

2 years ago

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Please Help! i am on the last stretch for a test, and i seriously need help with this question. i know its lame, but i really am

Romashka-Z-Leto [24]

I believe that it's A neither, because I don't think that it could be displayed on a coordinate graph when it has an exponent in it. So I think it's A. Let me know if I'm correct. ;-)

3 0

2 years ago

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One base of a triangular prism has two sides that are 15 inches wide and 10 inches long what is the possible length for the thir

Tcecarenko [31]

18.03 inches
Put the dimensions into the pythagorean theorem, that will give you the answer.

7 0

3 years ago