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HACTEHA [7]
2 years ago
10

What is the range of y = (x - 5)^2 – 1?

Mathematics
1 answer:
Setler79 [48]2 years ago
8 0

1.  The graph is a parabola.

2. The parabola opens up, because there's no negative number in front of (x-5)^2.

3. The vertext is (5,-1), because of the vertex form.

This means that that -1 will be the least y-value used on the graph and the garph will open up from there.

The range is (-1, infinity) or { y | y > -1 }.

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How many times greater is the value of the 3 in 4,367 than the value of the 3 in 39?​
Lesechka [4]

Answer: Roughly 111.97

Step-by-step explanation:

1. 39 divided by 3 is 13.  

2. 4367 divided by 3 is not evenly distributed. Rounding, it would work out to be roughly 1455.66 

3. 1455.66 divided by 13 is roughly 111.97 (Again, this does not distribute evenly)

4. To check your work, multiply 111.97 times 13 and you should get somewhere around 1455.66 which is (4367 divided by 3).

Hopefully this helps! Feel free to mark brainliest! :)

8 0
3 years ago
PLEASE HELP<br>Is the function linear or nonlinear y=1/x ?<br><br> A. linear B. nonlinear
Rina8888 [55]
It's nonlinear.
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8 0
3 years ago
Read 2 more answers
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stepladder [879]

Answer:

B

Step-by-step explanation:

Rate, in this case, is mph which can be written as miles/hours.

HTH :)

7 0
2 years ago
What is the inverse (opposite) of addition?
madam [21]

Answer:

Subtraction is the inverse (opposite operation) of addition

Step-by-step explanation:

4 0
3 years ago
Toni drives her car 99 mi on the highway on 3 gal of gas. At this rate how many miles can she drive on 11 gal of gas?
Helen [10]

Answer:

333.67 miles

Step-by-step explanation:

She drives her car 91 mi on 3 gal of gas

That’s 91 mi = 3 gal

How many miles can she drive on 11 gal of gas .

Let the mile she can drive by 11 gal of gas be A

At the same rate ,

91 mi = 3 gall

A mi = 11 gal

Cross multiply

A x 3 = 91 x 11

A x 3 = 1001

Divide both sides by 3

A x 3/3 = 1001/3

A = 333.67 miles

At the same rate she’ll drive 333.67 miles on 11 gal of gas

4 0
2 years ago
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