WZ←→− is tangent to circle O at point B.

Mathematics

2 answers:

Assoli18 [71]4 years ago

7 0

A tangent (here WZ in the question) to any circle (here O in the question) is a line segment that touches the circle at only one point (here B in the question) on circumference of circle, and the radius of the circle (here OB in the question) through this point is always perpendicular to that particular tangent.

In other words, Tangent (WZ) and Radius (OB) of any circle (O) always make a Right angle at point of intersection (B) on its circumference.

It means angle ∠OBZ would be a Right angle i.e. 90 degrees.

So, option B i.e. 90 degrees is the final answer.

melisa1 [442]4 years ago

7 0

The answer to this is 90°

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Donte simplified the expression below. 4 (1 3 i) minus (8 minus 5 i). 4 3 i minus 8 5 i. negative 4 8 i. what mistake did donte

SCORPION-xisa [38]

Donte did a mistake that 'he did not apply the distributive property correctly for 4(1 3i)' option (A) is correct.

<h3>What is a complex number?</h3>

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have an expression:

= 4(1 + 3i) – (8 – 5i)

= 4 + 12i - 8 + 5i

He did not distribute the subtraction sign correctly for 8 – 5i.

= -4 + 17i

Thus, Donte did a mistake in that 'he did not apply the distributive property correctly for 4(1 3i)' option (A) is correct.

Learn more about the complex number here:

brainly.com/question/10251853

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