√58 what would be the answer to this?

A water balloon has a diameter of 6 inches. How many cubic inches of water does it contain when it is 3/4 full

Travka [436]

Below are the choices that can be found from other sources:

A) 36 pi
B) 6 pi 
C) 27 pi 
D) 216 pi 
E) 48 pi

A sphere's volume is (4/3)*pi*r^3.
The diameter of the balloon is 6 inches. The diameter is twice the radius. The radius is 3 inches. 

(4/3)*pi*3^3 = 36 * pi 

But the balloon is only 3/4 full. So 

36 * (3/4) * pi = 27 * pi. 

The balloon has 27 pi cubic inches of water.

7 0

3 years ago

-3.667987=b^(-2)w+(-1.981902-w)

xxTIMURxx [149]

Answer:

what are the answers?

Step-by-step explanation:

7 0

4 years ago

Help please solve <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1

Shkiper50 [21]

Answer:

$\displaystyle -\frac{1}{2} \leq x < 1$

Step-by-step explanation:

Inequalities

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

$\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0$

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

$\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0$

Simplifying by x-1 and taking x=1 out of the possible solutions:

$\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0$

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

$(6x^3+14x^2+10x+12)$

is always positive and doesn't affect the result. It can be neglected. The expression

$(x-\frac{1}{2})^2$

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

$\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0$

For the expression to be negative, both signs must be opposite, that is

$(x+\frac{1}{2})\geq 0, (x-1)$

Or

$(x+\frac{1}{2})\leq 0, (x-1)>0$

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

$\displaystyle -\frac{1}{2} \leq x < 1$

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

$\boxed{\displaystyle -\frac{1}{2} \leq x < 1 }$

7 0

3 years ago

4+2×1+3? How do u solve this please?

Bad White [126]

Answer:

7

Step-by-step explanation:

PEMDAS multiply 2 times 1 then add 4 and 3

7 0

3 years ago

Read 2 more answers

A train travels from Tutuban to Calamba station. The distance between Tutuban and Calamba is defined by the function d(x) = x4 +

svlad2 [7]

given :

d(x) = x^4 + x^3 + 3x^2 + 4x - x kilometers.

t(x) = x

presumably the same value of x is used in both equations.

distance traveled is a function of time traveled, and that this relationship is preserved for any given speed.

Formula

r × t = d

r is the rate in kilometers per hour.

t is the time in hours.

d is the distance in hours.

based on the formulas you are given, this becomes:

r * t(x) = d(x)

if the train travels for 2 hours, then:

t(x) = t(2) = 2

d(x) = x^4 + x^3 + 3x^2 + 4x - x

d(2) = 2^4 + 2^3 + 3*2^2 + 4*2 - 2

d(2) = 42.

hence, t(2) = 2 and d(2) = 42

if the trip takes 2 hours, then the distance traveled is 42 kilometers based on the value of x = 2 in both equations.

the rate * time = distance equation of r * t(x) = d(x)

r × 2 = 42

r = 42/2

= 21.

this says the train will travel 42 kilometers in 2 hours if the train travels at 21 kilometers per hour.

4 0

3 years ago