Answer:
The organelles in an animal cell are as follows:
cell membrane, nucleus, nucleolus, nuclear membrane, cytosol, smooth endoplasmic reticulum, rough endoplasmic reticulum, Golgi apparatus, ribosomes, mitochondria, centrosome, cytoskeleton, vacuoles, vesicles, and lysosomes.
Explanation:
An animal cell is a typical example of an eukaryotic cell i.e a cell that contains a membrane-bound nucleus. In the cell are certain structures that performs specific functions in the cell called ORGANELLES. The organelles, according to this question, are found suspended or cushioned in the cytoplasm of the animal cell.
A list of the organelles in the cytoplasm (part of the cell that excludes the nucleus) of an animal cell are as follows:
- cell membrane
- nucleus
- nucleolus
- nuclear membrane
- cytosol
- smooth endoplasmic reticulum
- rough endoplasmic reticulum
- Golgi apparatus
- ribosomes
- mitochondria
- centrosome
- cytoskeleton
- vacuoles
- vesicles
- lysosomes
<span>There is a possibility that the population of mice will go way down or even become extinct.</span>
Answer: Atoms were created after the Big Bang 13.7 billion years ago. As the hot, dense new universe cooled, conditions became suitable for quarks and electrons to form. Quarks came together to form protons and neutrons, and these particles combined into nuclei.
The answer your looking for is 20 Amino Acids.<span>
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Answer:
42,5 mL
Explanation:
We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.
<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>
The first step is to have the same measurment unit so we need to convert 345 µg to mg.
we know that 1 µg equals 0,001 g, hence:
now the final volume is 0,345 mg protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula
Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL
So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)
