Answer:
The answer is given below
Explanation:
The 2 traits of the agouti fur mice are determined by non linked genes, which assort independently.
For this purpose we will use the multiplication rule to calculate the probability of agouti brown offspring (A_ bb) from AaBb parents.
The probability of A_ offspring is 3/4 and the probability of offspring bb is 1/4.
The total probability will be 3/4 x 1/4 = 3/16.
Answer:
i do not know Explanation:
Answer:
Genotype: Bb (heterozygous)
Phenotype: brown fur
Explanation:
Since allele B is dominant to allele b, as long as genotype has allele B in it, its effect of phenotype will be expressed instead, regardless of whether allele b is present.
As mouse genotype is stated as Bb, on the chromosome from its parents, allele B comes from one parent while allele b is inherited from the other parent.
Phenotype is the expressed trait. In this case, as genotype has allele B, the phenotype will be brown fur as its effect is expressed.
Established on the data, sickle cell hemoglobin displays altered primary structure and altered quaternary structure; the secondary and tertiary structures may or may not be altered. The sickle cell disease is a cluster of disorders that disturbs hemoglobin, the molecule in red blood cells that transports oxygen to cells all over the body. A person with this disorder have uncharacteristic hemoglobin molecules named hemoglobin S which can interfere with red blood cells into a sickle or crescent shape.
