$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
\begin{array}{lllcll}
y=&6(x-&1)^2&-8\\
&\uparrow &\uparrow &\uparrow \\
&a&h&k
\end{array}$

5 0

2 years ago

Which partial quotients could be added to find 396 ÷ 12?

Travka [436]

Answer:

33 plz braniest i think i help you

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The isosceles triangle shown has a base of 4 y + 2 and a perimeter of 6 y + 12 . Which expression represents the length of 1 o

liberstina [14]

Answer:

The expression that represents the length of 1 of the triangle's legs is y + 5

Step-by-step explanation:

An isosceles triangle has two sides equal which are the triangle legs. Let b represent the base of the triangle and l represent one of the triangle's legs. Then, the perimeter, P is given by

P = l + l + b

i.e P = 2l + b

From the question, P = 6y + 12 and b = 4y +2

∴ 6y + 12 = 2l + 4y + 2

6y - 4y + 12 - 2 = 2l

2y + 10 = 2l

∴ 2l = 2y + 10

Then,

l = (2y+10)/2

l = y + 5

Hence, the expression that represents the length of 1 of the triangle's legs is y + 5

4 0

3 years ago