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2 years ago

How do you know when an expression is in it’s simplest form?

Mathematics

1 answer:

k0ka [10]2 years ago

3 0

Answer:

In general, an expression is in simplest form when it is easiest to use.

Step-by-step explanation:

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I need help figuring this out can someone help me

Reil [10]

I think the answer is b

4 0

3 years ago

Read 2 more answers

Which expression calculates the speed in meters per second of an object that travels a distance of 100 m every 20 s?

QveST [7]

A. 100/20

The distance in meters should be divided by the time in seconds to get the value of the distance in meters travelled in one second.

8 0

3 years ago

The following table shows the salary of 7 people in an office last year.

kotegsom [21]

Answer:

a. £24,714.29

b. £16,833.33

Step-by-step explanation:

The calculation of mean income is given below:-

Mean income = Total addition of salaries ÷ Number of workers

= £9,500 + £25,000 + £13,250 + £72,000 + £12,750 + £29,500 + £11,000

= £173,000 ÷ 7

= £24,714.29

Now,

the Mean income excluding Deva's salary:

= Formula of Mean income

= Total addition of salaries excluding Deva salary ÷ Number of workers

= (£9,500 + £25,000 + £13,250 + £12,750 + £29,500 + £11,000) ÷ 6

= £101,000 ÷ 6

= £16,833.33

7 0

3 years ago

Rita's company reimburses her expenses on food, lodging, and conveyance during business trips. The company pays $55 a day for fo

ELEN [110]

0.45×300= 135 2,335 - 135=2,200 2,200÷55= 40
⬆ ⬆ ⬆
This is how This is how much This is how many
much they paid was left in the days they paid for food
for the miles reimbursement and lodging
traveled

Part A: X= (2,335- ( 0.45 ×300) ) ÷55
Part B: I dont know how to do algebraic property of equality.
Part C: They spent 40 days or 1 month , one week and 3 days

7 0

3 years ago

What is the form of the two squares identity?

zvonat [6]

Answer:

Step-by-step explanation:

Consider all options:

A. False, because

$(a^2+b^2)(c^2+d^2)=a^2c^2+a^2d^2+b^2c^2+b^2d^2\\ \\(ab-cd)^2+(ac+bd)^2=a^2b^2-2abcd+c^2d^2+a^2c^2+2abcd+b^2d^2=\\ =a^2b^2+c^2d^2+a^2c^2+b^2d^2\\ \\a^2c^2+a^2d^2+b^2c^2+b^2d^2\neq a^2b^2+c^2d^2+a^2c^2+b^2d^2$

B. False, because

$(a^2-b^2)(c^2+d^2)=a^2c^2+a^2d^2-b^2c^2-b^2d^2\\ \\(ac-bd)^2-(ad+bc)^2=a^2c^2-2abcd+b^2d^2+a^2d^2+2abcd+b^2c^2=\\=a^2c^2+b^2d^2+a^2d^2+b^2c^2\\ \\a^2c^2+a^2d^2-b^2c^2-b^2d^2\neq a^2c^2+b^2d^2+a^2d^2+b^2c^2$

C. False, because

$(a^2+b^2)(c^2-d^2)=a^2c^2-a^2d^2+b^2c^2-b^2d^2\\ \\(ac+bd)^2-(ad+bc)^2=a^2c^2+2abcd+b^2d^2-a^2d^2-2abcd-b^2c^2=\\=a^2c^2+b^2d^2-a^2d^2-b^2c^2\\ \\a^2c^2-a^2d^2+b^2c^2-b^2d^2\neq a^2c^2+b^2d^2-a^2d^2-b^2c^2$

D. True, because

$(a^2+b^2)(c^2+d^2)=a^2c^2+a^2d^2+b^2c^2+b^2d^2\\ \\(ac-bd)^2-(ad+bc)^2=a^2c^2-2abcd+b^2d^2+a^2d^2+2abcd+b^2c^2=\\=a^2c^2+b^2d^2+a^2d^2+b^2c^2\\ \\a^2c^2+a^2d^2+b^2c^2+b^2d^2= a^2c^2+b^2d^2+a^2d^2+b^2c^2$

6 0

3 years ago