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Ne4ueva [31]
2 years ago
10

How do you know when an expression is in it’s simplest form?

Mathematics
1 answer:
k0ka [10]2 years ago
3 0

Answer:

In general, an expression is in simplest form when it is easiest to use.

Step-by-step explanation:

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Please helppp me anyone​
Irina18 [472]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
8\3as a mixed number
Ber [7]

2 2/3

hope i helped. (:

7 0
3 years ago
Read 2 more answers
During the first stages of an epidemic, the number of sick people increases exponentially with time. Suppose that at = 0 days th
nydimaria [60]
T = days passed

r = rate of growth

by 0 day, or t = 0, there are 2 folks sick,

\bf \qquad \textit{Amount for Exponential Growth}
\\\\
A=P(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &2\\
P=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &0\\
\end{cases}
\\\\\\
2=P(1+r)^0\implies 2=P\cdot 1\implies 2=P\qquad \boxed{A=2(1+r)^t}

 by the third day, t = 3, there are 40 folks sick,

\bf \qquad \textit{Amount for Exponential Growth}
\\\\
A=P(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &40\\
P=\textit{initial amount}\to &2\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &3\\
\end{cases}
\\\\\\
40=2(1+r)^3\implies 20=(1+r)^3\implies \sqrt[3]{20}=1+r
\\\\\\
\sqrt[3]{20}-1=r\implies 1.7\approx r\qquad \boxed{A=2(2.7)^t}

how many folks are there sick by t = 6?   \bf \stackrel{that~many}{A=2(2.7)^6}
8 0
3 years ago
647.2 + 12.88 how to answer that step by step
IgorC [24]

Answer:

660.08

Step-by-step explanation:

1. first you will need to line up the decimals and make sure the places are correct

 647.2

+   12.88

2. Then you just add them

4 0
3 years ago
In the coordinate plane, draw quadrilateral ABCD with A(–5, 0), B(2, –6), C(8, 1), and D(1, 7), then demonstrate that ABCD is a
Len [333]

Answer:

ABCD is a rectangle

Step-by-step explanation:

∵ A = (-5 , 0) , B = (2 , -6) , C = (8 , 1) , D = (1 , 7)

∵ The x-coordinate of the mid-point of AC = (-5 + 8)/2 =3/2

∵ The y-coordinate of the mid-point of AC = (0 + 1)/2 = 1/2

∴ The mid-point of AC = (3/2 , 1/2)

∵ The x-coordinate of the mid-point of BD = (2 + 1)/2 =3/2

∵ The y-coordinate of the mid-point of BD = (-6 + 7)/2 = 1/2

∴ The mid-point of BD = (3/2 , 1/2)

∴ The mid-point of AC = The mid-point of BD ⇒ (1)

∵ AC = √[(8 - -5)²+(1 - 0)² = √170

∵ BD = √[(1 - 2)²+(7 - -6)² = √170

∴ AC = BD ⇒ (2)

From (1) and (2)

AC and BD equal each other and bisects each other

∴ ABCD is a rectangle

7 0
3 years ago
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