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Verdich [7]
3 years ago
10

Subtract 2.53 x 105 from 1.3 x 108​

Mathematics
2 answers:
xeze [42]3 years ago
5 0

Answer:

125.2 is your answer dear

kkurt [141]3 years ago
4 0

Answer:

Step-by-step explanation:

2.53 x 105 is 265.65

1.3 x 108​ is 140.4

now, Subtract 2.53 x 105 from 1.3 x 108​

140.4 - 265.65

= -125.25

Hope this helps

plz mark as brainliest!!!!!!

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What is the question of the line that passes through the point (-2,-2) and has a slope of 4. Plz someone answer
Studentka2010 [4]

Answer:y=4x+6

Step-by-step explanation:

We have the information that the slope is 4 and the line goes through the point (-2,-2). With this information, we can make a linear equation in a point slope form (y - y_{1}= m * (x - x_{1}), so the equation would be y+2=4(x+2), or simplified, y+2=4x+8. in order to solve for y (to make it a slope-intercept equation), we must subtract 2 from both sides. This gives us the equation y=4x+6. Hope this helps!

4 0
3 years ago
Is (9, 90) a solution to the equation y = 10x?<br>yes​
Galina-37 [17]

Use the substitution method

(9,90) y= 10x

90= 10(9)

90= 90

Answer is yes

5 0
3 years ago
Read 2 more answers
Please help
shtirl [24]

Answer:

Step-by-step explanation:

The slope of the line in question is the same as the slope of the line parallel to it. Using y = mx + b, where m is the slope, we find the slope of our line is -3.

Using the pt-slope form, y - y1 = m( x - x1), we get y - (-1) = -3( x - 2) or y + 1 = -3x + 6. Which leads us to y = -3x + 5. QED

4 0
2 years ago
A.(-1,6)<br> B.(-6,5)<br> C.(-8,1)<br> D.(-10,1)<br><br> HELP ASAP‼️‼️
Evgen [1.6K]

Answer:

the answer is b

Step-by-step explanation:

I did this last year and got them right

3 0
3 years ago
An object launched vertically from a point that is 37.5 feet above ground level with an initial velocity of 48.6 feet per second
Elis [28]

Answer: 3.675 seconds

Step-by-step explanation:

Hi, when the object hits the ground, h=0:

h=−16t^2+48.6t+37.5

0=−16t^2+48.6t+37.5

We have to apply the quadratic formula:  

For: ax2+ bx + c  

x =[ -b ± √b²-4ac] /2a  

Replacing with the values given:  

a=-16 ; b=48.6; c=37.5

x =[ -(48.6) ± √(-48.6)²-4(-16)37.5] /2(-16)  

x = [ -48.6 ± √ 4,761.96] /-32

x = [ -48.6 ± 69] /-32

Positive:  

x = [ -48.6 + 69] /-32 = -0.6375

Negative:  

x = [ -48.6 - 69] /-32 = 3.675 seconds (seconds can't be negative)

Feel free to ask for more if needed or if you did not understand something.  

8 0
3 years ago
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