Answer:
a = 3
b= -1
c = 5
X = (-b +- sqrt [b^2 - 4ac]) / 2a
X = (--1 +- sqrt (1 - 4*3 * 5)) / 2* 3
x = (1 += sqrt (1 -60)) / 6
x1 = (1 + sqrt (-59)) / 6
x2 = (1 - sqrt (-59)) / 6
Source: http://www.1728.org/quadratc.htm
Step-by-step explanation:
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Answer:
-3 1/3
Step-by-step explanation:
The quadratic
... y = ax² +bx +c
has its extreme value at
... x = -b/(2a)
Since a = 3 is positive, we know the parabola opens upward and the extreme value is a minimum. (We also know that from the problem statement asking us to find the minimum value.) The value of x at the minimum is -(-4)/(2·3) = 2/3.
To find the minimum value, we need to evaluate the function for x=2/3.
The most straightforward way to do this is to substitue 2/3 for x.
... y = 3(2/3)² -4(2/3) -2 = 3(4/9) -8/3 -2
... y = (4 -8 -6)/3 = -10/3
... y = -3 1/3
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<em>Confirmation</em>
You can also use a graphing calculator to show you the minimum.
