Which of the following is the minimum value of the equation y = 3x^2 − 4x − 2?
1 answer:
Answer:
-3 1/3
Step-by-step explanation:
The quadratic
... y = ax² +bx +c
has its extreme value at
... x = -b/(2a)
Since a = 3 is positive, we know the parabola opens upward and the extreme value is a minimum. (We also know that from the problem statement asking us to find the minimum value.) The value of x at the minimum is -(-4)/(2·3) = 2/3.
To find the minimum value, we need to evaluate the function for x=2/3.
The most straightforward way to do this is to substitue 2/3 for x.
... y = 3(2/3)² -4(2/3) -2 = 3(4/9) -8/3 -2
... y = (4 -8 -6)/3 = -10/3
... y = -3 1/3
_____
<em>Confirmation</em>
You can also use a graphing calculator to show you the minimum.
You might be interested in
Answer:
(a) 720 ways
(b) 120 ways
(c) 24 ways
Step-by-step explanation:
Given
--- number of letters
Solving (a): Number of arrangements.
We have:
So, the number of arrangements is calculated as:
This gives:
This gives:
Solving (b): DA as a unit
DA as a unit implies that, we have:
[DA] N C E R
So, we have:
So, the number of arrangements is calculated as:
This gives:
This gives:
Solving (c): NCE as a unit
NCE as a unit implies that, we have:
D A [NCE] R
So, we have:
So, the number of arrangements is calculated as:
This gives:
This gives: