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Nikitich [7]
3 years ago
8

Rearrange the equation so m is the independent variable. -2m-5n=7m-3n n=___

Mathematics
1 answer:
Aneli [31]3 years ago
3 0
<h2>Answer:</h2>

The equation is given by:

        n=\dfrac{-9}{2}m

<h2>Step-by-step explanation:</h2>

We are given a equation in terms of the variable m and variable n as follows:

-2m-5n=7m-3n

Now, we are asked to find the equation in terms of m i.e. we have to consider m as independent variable and n as dependent variable since it's value is to be expressed in terms of m.

Now, we add 5n on both the sides of the equation to get:

-2m=7m-3n+5n\\\\i.e.\\\\-2m=7m+2n

Now, we subtract 7m from both the sides of the equation to get:

-2m-7n=2n\\\\i.e.\\\\2n=-9m\\\\n=\dfrac{-9}{2}m

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Which term best describes the graph of y = -2X + 4
Alexxandr [17]

Answer:

Decreasing, negative slope

Step-by-step explanation:

Bc the slope is -2x in this equation therefore its a negative slope.

3 0
2 years ago
Segments
Kazeer [188]

Given

AB  and  CD  intersect

AC,  CB,  BD  and  AD  are congruent.

Prove that AB  is the bisector of ∠CAD and ray  CD  is the bisector of ∠ACB.

and AB  and  CD  are perpendicular.

To proof

Bisector

<em>A bisector is that which cut an angle in two equal parts.</em>

In ΔACB and ΔADB

AD = AC  ( Given )

AB = AB   ( common )

BC = DB  ( Given )

by SSS congurence property

we have

ΔACB ≅ΔADB

∠CAB =∠ DAB

∠CBA = ∠DBA

( By corresponding sides of the congurent triangle )

Thus AB is the bisector of the ∠CAD.

InΔ DAC and ΔDBC

AD = DB (Given)

AC = CB  ( Given )

CD = CD (common)

By SSS congurence property

ΔDAC≅ Δ DBC

∠  ACD =∠ BCD

∠ADC =∠BDC

( By corresponding sides of the congurent triangle )

Therefore CD is the bisector of the CAD.

In ΔBOC andΔ BOD

BO = BO ( Common )

∠BCO = ∠BDO

( As prove above ΔACB ≅ΔADB

Thus ∠ACB = ∠ADB by corresponding sides of the congurent triangle , CD is a bisector

∠BCO = ∠BDO )

 CB = DB ( given )

by SAS congurence property

ΔBOC ≅ ΔBOD

∠BOC =∠ BOD

∠BOC +∠ BOD = 180 °( Linear pair )

2∠ BOC = 180°

∠BOC = 90°

∠BOC =∠ BOD = 90°

also

In ΔCOA and ΔAOD

AO = AO ( Common )

∠ACO =∠ ADO

(  As prove above ΔACB ≅ΔADB Thus ACB = ADB by corresponding sides of congurent triangle ,CD is a bisector

thus  ∠ACO = ∠ADO )

AC =AD ( given )

by SAS congurence property

Δ COA ≅ ΔAOD

∠AOC = ∠AOD

( By corresponding angle of corresponding sides )

∠AOC + ∠AOD = 180°

2∠ AOC = 180°   ( Linear pair )

∠AOC = 90°

∠AOC = ∠AOD = 90 °

Thus AB  and  CD  are perpendicular.

Hence proved









   


 



6 0
3 years ago
Is (0,0) a solution to this system?
Anuta_ua [19.1K]

Answer:

option-B

Step-by-step explanation:

we are given system of inequality as

y\leq x^2-4

y>2x-1

now, we can check solution

At (0,0):

we can plug x=0 and y=0

and check inequality

0\leq 0^2-4

0\leq -4

so, this is FALSE

now, we can check second inequality

0>2\times 0-1

0>-1

So, this is TRUE

so, option-B

5 0
3 years ago
Read 2 more answers
What is –12x–9=–6y in standard form?
Mars2501 [29]
-12x - 9 = -6y
-12x + 6y  -9 = 0

-12x + 6y = 9  is the answer

5 0
3 years ago
What number needs to be added to both sides of the equation in order to complete the square?
Sever21 [200]

x^2+14x = (x+7)^2

7^2 = 49

so you would add 49 to both sides

5 0
3 years ago
Read 2 more answers
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