2 years ago

Please help!! I need an answer fast!

1 answer:

7 0

The median of the data set is 4. The interquartile range is UQ-LQ 5-3=2. The mean of the first set is 3.5. The mean of the second set is 5.5. Since every score went up by two, the mean went up by two as well.

I hope that helps.

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<img src="https://tex.z-dn.net/?f=g%28x%29%20%3D%203x%20-%206" id="TexFormula1" title="g(x) = 3x - 6" alt="g(x) = 3x - 6" align=

VARVARA [1.3K]

Hey there! :)

Answer:

$g^{-1} (g(10))=10$

Step-by-step explanation:

Begin by calculating g(10):

g(x) = 3x - 6

Substitute in 10 for x:

g(10) = 3(10) - 6

g(10) = 30-6

g(10) = 24.

Plug '24' into 'x' into $g^{-1} (x)$

$g^{-1} (24)=\frac{(24) + 6}{3}$

Simplify:

$g^{-1} (24)=\frac{30}{3}$

$g^{-1} (24)=10$

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2 years ago

According to Ohm’s law, which is stated as I = V ÷ R, which two sentences are true?

Sladkaya [172]

Answer:

2nd and 3rd

Step-by-step explanation:

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2 years ago

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The rabbit population in a certain area is 500% of last years population. There are 900 rabbits this year. How many were there t

12345 [234]

Answer:

180 rabbits

Step-by-step explanation:

<u><em>The correct question is</em></u>

The rabbit population in a certain area is 500% of last years population. There are 900 rabbits this year. How many were there last year?

we know that

900 rabbits represent 500% of last year population

Last year population represent 100%

using proportion

Find out how many rabbits represent a percentage of 100%

$\frac{900}{500\%}=\frac{x}{100\%}\\\\x=900(100)/500\\\\x=180\ rabbits$

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Step-by-step explanation:

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