To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.
a. (f+g)(x) = 8x+2
b. (f-g)(x) = 4x-6
Step-by-step explanation:
Given
<u>a. (f+g)(x)</u>
<u>b. (f-g)(x)</u>
Hence,
a. (f+g)(x) = 8x+2
b. (f-g)(x) = 4x-6
Keywords: Functions
Learn more about functions at:
#LearnwithBrainly
Answer:
x ≈ 14.57
Step-by-step explanation:
using the sine ratio in the right triangle
sin59° = =
( multiply both sides by 17 )
17 × sin59° = x , then
x ≈ 14.57 ( to 2 dec. places )