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const2013 [10]
3 years ago
15

Solve using Substitution y = 6x - 11 -2x - 3y = -7

Mathematics
1 answer:
vladimir2022 [97]3 years ago
4 0

Answer:

(2, 1)

Step-by-step explanation:

To solve by substitution, we solve one equation for one of its variables and then substitute the solved value for that variable into the other equation. Because this system of equations already has one solved for the variable, this makes our job much easier. We only need to implement the solved value for y into the other equation and solve for x.

y = 6x - 11

-2x - 3(6x - 11) = -7 Distribute.

-2x - 18x + 33 = -7 Combine like terms.

-20x + 33 = -7 Subtract 33 from both sides of the equation.

-20x = -40 Divide by -20 on both sides of the equation.

x = 2

Then, with this value, we will place it into the equation that was already solved for y in order to get a definite value for y.

y = 6(2) - 11

y = 12 - 11

y = 1

Using this information, the coordinate pair for this equation (the point of intersection between the two lines) is (2, 1).

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The answer is:  [B]:  " -10a + 6b² − 4b + 3 " .
_____________________________________
Explanation:
____________________
Given:
____________________________
  -2(5a − 3b²) − 4b + 3 ;  
_________________________________
    "Use the distributive property [of multiplication] to expand the expression."
______________________________________________
Note the distributive property of multiplication:
______________________________________________
           a(b + c) = ab + ac ;
           a(b − c) = ab − ac ;
______________________________________________
So, we have:  " -2(5a − 3b²) − 4b + 3 "  ;
______________________________________________

Start  with:  " -2(5a − 3b²) " ; 
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   -2(5a − 3b²)  =  (-2*5a) − (-2*3b²)  =  (-10a) − (-6b²)
 
           =  -10a + 6b²
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        → Now, bring down the rest of the problem; 
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  -10a + 6b² − 4b + 3 ;  which is:  Answer choice:  [B].
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