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zmey [24]
3 years ago
6

Ms.lu is adding a new room to her house. The room will be a cube with volume 4,913 cubic feet.What is tje length of the new room

Mathematics
2 answers:
wolverine [178]3 years ago
3 0
Oh my gosh!

i have this exact question on my homework and i am so confused 

Alex73 [517]3 years ago
3 0

Answer: 17 feet

Step-by-step explanation:

Given : Ms.lu is adding a new room to her house. The room will be a cube with volume 4,913 cubic feet.

Let s be the side of the square-room.

We know that the volume of a square is given by :-

\text{Volume}=s^3

Then for the given room we have

s^3=4,913

Taking cube root on both sides , we get

s=\sqrt[3]{4913} =17

Hence, the length of the new room = 17 feet.

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levacccp [35]

Answer: 540

Step-by-step explanation: hope this helped

8 0
3 years ago
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What’s the answer?and how do you get it
Kay [80]

the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.

from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.

the standing up sides are simply rectangles of 8x3.

if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.

\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312

7 0
3 years ago
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

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8 0
3 years ago
6 = -5 -x solve for x
makkiz [27]

Answer:

<h2>x = -11</h2>

Step-by-step explanation:

In algebra, the goal is always to isolate the variable, so that its value can be determined.

<h3>Step 1: Add x</h3>

6 + x = -5

<h3>Step 2: Subtract 6</h3>

x = -11

<h3>Step 3: Check</h3>

6 = -5 - -11

6 = -5 + 11

6 = 6 ✔

<h3>Step 4: Answer</h3>

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I'm always happy to help :)

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Help please :]!!<br> please be right,
pickupchik [31]
I think it’s c I had this question lol
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