The answer is 6 cm. The mid segment is half of BC
-4m-24=-8
(add 24 to both sides)
-4m=16
(divide by -4 on both sides)
m=-4
Answer:
Hello! After reading your question I have deduced that the correct answer is 288² cm.
Step-by-step explanation:
The way I came to this conclusion was as follows:
Firstly:
If said rectangle is two squares put side by side (adjacent), then a valid assumption is that both squares are the same size.
This is because all four sides of a square have to be equal.
Thus if the two squares are joined together on one side, then all the other sides of both the squares will be the same length.
Thus both of the squares are going to be the same size, so they will have the same area.
Secondly:
If the area of one square is 144² cm then the area of the other square should also be 144² cm.
Thus if you combine the areas of both the squares, that make up the rectangle, you are left with the area of the rectangle being 288² cm.
I hope this helped!
I think task 1 is B
Hope this helps
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The answer would be 30%
Explanation~
Well, you would have to add 27 and 23 first since, it says, “What percentage of the twelfth grade students have more than one college in mind” then, you’d have to figure out the percentage from there. And the percentage would be, 29.4117647059% of 170, round that to the nearest percent and it’s 30 I’m pretty sure.
