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DerKrebs [107]
4 years ago
8

How do we test a graph to see if it is a function

Mathematics
1 answer:
ioda4 years ago
7 0

Answer:

You look it up

Step-by-step explanation:


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• On Monday the school bus traveled the Green Route 8 times and the Blue Route 9 times, traveling a total of 95 miles. • On Tues
hoa [83]

Answer: Green route = 5.8 miles

Blue route = 5.4 miles.

Step-by-step explanation:

Let the miles travelled for Green route be x

Let the miles travelled for Blue route be y

We can form an equation from the question given which will be:

8x + 9y = 95 ........ i

12x + 6y = 102 ......... ii

Multiply equation i by 12

Multiply equation ii by 8

96x + 108y = 1140 ....... iii

96x + 48y = 816 ....... iv

Subtract iv from iii

60y = 324

y = 324/60 = 5.4

Blue route is 5.4 miles.

Since 8x + 9y = 95

= 8x + 9(5.4) = 95

8x + 48.6 = 95

8x = 95 - 48.6

8x = 46.4

x = 46.4/8 = 5.8

Green route = 5.8 miles

3 0
3 years ago
What is 5 ½ x 4? Qwer​
const2013 [10]

Answer:

5.5 time 4 equals 22

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Jill arranges quarters in stacks of increasing powers of 2, starting with the zeroth power (20). If she ends up with six stacks,
Ratling [72]
Stack 1 : 2^0 = 1 quarter.
Stack 2 : 2^1 = 2 quarters.
Stack 3: 2^2 = 4 quarters.
Stack 4: 2^3 = 8 quarters.
Stack 5 : 2^4 = 16 quarters.
Stack 6: 2^5 = 32 quarters.
1 + 2 + 4 + 8 + 16 + 32 = 63
Answer: She used 63 quarters. 
8 0
4 years ago
A solid object is dropped into a pond with a temperature of 20 degrees Celsius. The function f(t)=Ce(−kt)+20 represents the situ
LenaWriter [7]

Answer:

The initial temperature of the object was 37.6 degrees Celsius

The initial temperature of the object was 37.6 (without units)

Step-by-step explanation:

we have

f(t)=Ce^{(-kt)} +20

where

f(t) represent the temperature of the object in degree Celsius

t is the time in minutes

<em>Find the value of the constant C</em>

we have the ordered pair (4,35)

substitute in the equation and solve for C

35=Ce^{(-0.0399*4)} +20

Ce^{(-0.0399*4)}=15

C=15/e^{(-0.0399*4)}

C=17.6

Find the initial value of the object

we know that

The initial temperature is the value of f(t) when the value of t is equal to zero

so

For t=0

f(0)=(17.6)e^{(-k*0)} +20

f(0)=17.6 +20

f(0)=37.6\ degrees\ Celsius

therefore

The initial temperature of the object was 37.6 degrees Celsius

The initial temperature of the object was 37.6 (without units)

3 0
3 years ago
Cylinder A has a volume of 100 cm and cylinder B has a height that two fifths of the height of cylinder A
Ivahew [28]

You need more input here what even is the question

6 0
3 years ago
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