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Kryger [21]
3 years ago
5

X/4 -7=y for x pls help

Mathematics
1 answer:
kondaur [170]3 years ago
6 0

Answer:

x=4(y+7) or x= 4y+28

Step-by-step explanation:

x/4 - 7 =y

solve for x means you want to make equation x =......

x/4 = y+7

x=4(y+7)

or

x=4y+28

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Which equation can be used to solve for x in the following diagram.
Romashka [77]

Answer:

11, A

Step-by-step explanation:

90 - 35 = 55

55/5 = 11

6 0
3 years ago
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Find the explicit formula for -3,-33,-63,-93
bagirrra123 [75]

Answer:

a n = -3+(n-1)-30

Step-by-step explanation:

-3 - 30 = -33

-33 - 30 = -63

-63 - 30 = -93

The common difference here is -30. d = -30

The explicit formula is a n = a1 + (n-1)d

5 0
3 years ago
Someone please give me the answers...And thank you
ale4655 [162]

Answer:

Step-by-step explanation:

1) 4x + 3 <= 3x - 5

Subtract 3 from both sides

4x + 3-3  <= 3x - 5 -3

4x  <= 3x - 8

Subtract 3x form both sides

4x - 3x <= 3x -3x - 8

x <= -8

6 0
3 years ago
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It is recommended that one fire extinguisher be available for every 6000 feet in the building write and solve an equation to det
Ulleksa [173]
135,000 divided by 6000 =22.5
x = 22.5
7 0
3 years ago
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A average amount of money on deposit in a savings account is $7500. Suppose a random sample of 49 accounts shows the average in
Valentin [98]

Answer:  

z=-3.79

p_v =2*P(z  

Step-by-step explanation:  

1) Data given and notation  

\bar X=6850 represent the mean average amount of money on deposit in savings account for the sample  

\sigma=1200 represent the population standard deviation for the sample  

n=49 sample size  

\mu_o =7500 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean for the amount of money on deposit in savings account differs from 7500, the system of hypothesis would be:  

Null hypothesis:\mu =7500  

Alternative hypothesis:\mu \neq 7500  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{6850-7500}{\frac{1200}{\sqrt{49}}}=-3.79  

4)P-value  

Since is a two-sided test the p value would be:  

p_v =2*P(z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average amount of money deposit in savings account its significantly different from 7500 tons at 1% of signficance.  

7 0
3 years ago
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