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KengaRu [80]
3 years ago
12

An ice cream parlor serves ice cream cones, milkshakes, and waffles with ice cream. The cost of an ice cream cone is $1.20, the

cost of a milkshake is $2.00, and the cost of a waffle with ice cream is $3.50. If 50% of the customers choose an ice cream cone, 30% choose a milkshake, and 20% choose a waffle with ice cream, what is the expected value of the cost of one item served at the parlor?
$0.99

$1.00

$1.90

$2.00
Mathematics
1 answer:
vivado [14]3 years ago
8 0
Expected value = Sum of Probability * Cost of each ice cream.

Expected value

=  50%* $1.20 + 30%* $2.00 + 2<span>0%* $3.50
</span>
=  0.50* $1.20 + 0.30* $2.00 + 0.2<span>0* $3.50
</span>
= $1.90

Expected value of the cost of one ice cream = $1.90 
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5 0
2 years ago
in a game the player wins if he rolls a 6 on a number cube if the number cube is rolled 18 times then what is a reasonable predi
Dmitry_Shevchenko [17]

Answer:

There would be 15 unsuccessful rolls

Step-by-step explanation:

6 0
2 years ago
Y is inversely proportional to x. When y=25, x=4 Work out y when x=20
ipn [44]

Answer:

y=5 when x=20

Step-by-step explanation:

Using the format for inverse proportions: y=k/x

To find k, substitute 25 in for y and 4 for x to find:

25=k/4 ⇒ k=100

Using this we can substitute k and x in for 100 and 20 to find:

y=100/20 ⇒ y=5

8 0
3 years ago
Sharon purchased a used car for $24,600. The car depreciates exponentially by 8% per
Tju [1.3M]

Answer:

The value of car after 5 years of exponentially depreciation is $16,213.36  

Step-by-step explanation:

The initial amount of the car = i = $24,600

The depreciates rate of interest applied = r = 8%

Let The value of car after n years = A  

The number of years = n = 5 years

Now,According to question

The value of car after n years = initial price of car  × (1-\dfrac{\textrm rate}{100})^{\textrm time}

Or, The value of car after 5 years = i × (1-\dfrac{\textrm r}{100})^{\textrm n}

Or, $A = $24,600 × (1-\dfrac{\textrm 8}{100})^{\textrm 5}

Or, $A = $24,600 × (0.92)^{5}

Or, $A = $24,600 × 0.65908

Or, $A = $16,213.36

So, The value of car after 5 years = A = $16,213.36

Hence , The value of car after 5 years of exponentially depreciation is $16,213.36  . Answer

5 0
3 years ago
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Snezhnost [94]

The distance between the two points is 5.4

Explanation:

The points are (-1,-9) and (1,-4)

The distance between the two points can be determined using the formula

d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Substituting the values in the formula, we get,

d=\sqrt{(1+1)^{2}+(-4+9)^{2}}

Adding the values,

d=\sqrt{2^{2}+5^{2}}

Squaring the terms, we get,

d=\sqrt{4+25}

Simplifying, we have,

d=\sqrt{29}=5.4

Thus, the distance between the two points is 5.4

7 0
3 years ago
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