All categories

3 years ago

Imagine that a chromosome was compared to a novel. Which of these would best represent a gene?

SAT

1 answer:

Ad libitum [116K]3 years ago

8 0

Answer: B, a sentence.

Since a chromosome contains tens of thousands of genes and is compared to a novel, it would only make sense for a gene to be less than a novel. We can eliminate C. D, chapter of the book is too generous.

A, on the other hand, contains is not generous enough.

Therefore, I think the answer should be B.

You might be interested in

Why would a person in north america not see the solar eclipse shown here?

sdas [7]

This is so hard to answer.

3 0

4 years ago

Plzzzzzzzzzzzzzzzzzzz help fast im running out of time

Nikitich [7]

Answer:

Explanation:

75 is the mode because it happens the most frequently.

4 0

3 years ago

Read 2 more answers

what is the best way to mulitily 500 and 400 hey i know this is for school but would any one like to talk for a bit

Mashutka [201]

Answer:

First multiply 5*4 you'll get 20

Then add the remaining zeros to it.

The answer is 200000

Explanation:

6 0

3 years ago

Read 2 more answers

Which three parts of this excerpt from mark twain's "the £1,000,000 bank-note" contain hyperbole?.

ruslelena [56]

Answer: The two hyperboles in this excerpt are: "I'll never forget you as long as I live" and "the mine is worth far more than he asks for it".

Explanation:

8 0

2 years ago

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len

Citrus2011 [14]

Answer:

The additional words is $2^n$

Explanation:

Given

$B(n) = 2^n$

Required

Determine the additional words; i.e. $B(n + 1) - B(n)$

From the given parameters, we have that;

B is a function of n

Such that;

$B(n) = 2^n$

To calculate $B(n+1)$ , we simply substitute n + 1 for n

$B(n) = 2^n$

$B(n + 1) = 2^{n + 1}$

Applying laws of indices

$B(n + 1) = 2^{n} * 2^1$

$B(n + 1) = 2^{n} * 2$

$B(n + 1) = 2(2^{n})$

Calculating Additional Binary Code;

$B(n + 1) - B(n)$

Substitute values for B(n + 1) and B(n)

$B(n + 1) - B(n) = 2(2^n) - 2^n$

Express $2^n$ as $2^ n * 1$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 1$

Express 1 as $2^0$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0$

Factorize

$B(n + 1) - B(n) = 2^n(2 - 2^0)$

$B(n + 1) - B(n) = 2^n(2 - 1)$

$B(n + 1) - B(n) = 2^n(1)$

$B(n + 1) - B(n) = 2^n$

Hence, the additional words is $2^n$

8 0

3 years ago