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1 year ago

What maximum capacitance can you form from these

SAT

1 answer:

Serga [27]1 year ago

8 0

The maximum capacitance that can be formed from the given capacitors is 9000.01 μF (in parallel)

<h3>How to find Maximum Capacitance?</h3>

We are given the capacitances as;

3200 μF, 5800 μF, and 0.0100 μF

Now, if the capacitors are in parallel, the equivalent capacitance is;

C_eq = C₁ + C₂ + C₃

Thus;

C_eq = 3200 μF + 5800 μF + 0.0100 μF

C_eq = 9000.01 μF

Now, if the capacitors are in series, the equivalent capacitance is;

1/C_eq = 1/C₁ + 1/C₂ + 1/C₃

Thus;

1/C_eq = (1/3200) μF + (1/5800) μF + (1/0.0100) μF

C_eq = 0.00999995 μF

Therefore the maximum capacitance that can be formed from the given capacitors is 9000.01 μF (in parallel)

Complete question is;

Consider three capacitors, of capacitance 3200 μF, 5800 μF, and 0.0100 μF. What maximum capacitance can you form from these?

Read more about Maximum Capacitance at; brainly.com/question/16668646

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Pat needs to determine the height of a tree before cutting it down to be sure that it will not fall on a nearby fence. the angle

Mekhanik [1.2K]

The height of the tree, which Pat needs to determine, before cutting it down to be sure that it will not fall on a nearby fence is 111 ft.

<h3>What is right angle triangle property?</h3>

In a right angle triangle, the ratio of the opposite side to the base side is equal to the tangent angle between them.

$\tan\theta=\dfrac{b}{a}$

Here, (b) is the opposite side, (a) is the base side.

Pat needs to determine the height of a tree before cutting it down to be sure that it will not fall on a nearby fence.

The angle of elevation of the tree from one position on a flat path from the tree is

$H=40^o$

From a second position,

$I=60\rm\; ft$

Farther along this path it is,

$b=30^o$

Let the distance between tree and first position is x. Thus, from the trigonometry,

$\tan 40=\dfrac{h}{x}\\h=x\tan 40$ ....1

The distance between tree and second position is (x+60) ft. Thus, again from the trigonometry,

$\tan 30=\dfrac{h}{x+60}\\h=(x+60)\tan 40$ ......2

Compare the equation 1 and 2,

$x\tan (40)=(x+60)\tan 30\\0.839x=0.577x+34.64\\0.839x-0.577x=34.64\\x=\dfrac{34.64}{0.262}\\x=132.25\rm\; ft$

Put this value in equation 1 as,

$h=(132.25)\times \tan40\\h\approx111\rm\;ft$

Thus, the height of the tree, which Pat needs to determine, before cutting it down to be sure that it will not fall on a nearby fence is 111 ft.

Learn more about the right angle triangle property here;

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2 years ago

Researchers are studying two different designs of computer keyboards

olga_2 [115]

There are several types of keboard designs and research is ongoing to improve their efficiency e,g QWERTY, QWERTZ and AZERTY keyboards

<h3>Types of Keyboards</h3>

Bellow is an extended list of the various types of keyboards

Qwerty Keyboards
Wired Keyboards
Numeric Keypads
Ergonomic Keyboards
Wireless Keyboards
USB Keyboards
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2 years ago

Which of the following would not be appropriate to ask someone you'd just met

Reika [66]

Where is the pic for this so I can answer

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3 years ago

Read 2 more answers

Friction: a 50-kg box is resting on a horizontal floor. A force of 250 n directed at an angle of 30. 0° below the horizontal is

sergejj [24]

The net forces on the box parallel and perpendicular to the surface, respectively, are

∑ F[para] = (250 N) cos(-30.0°) - F[friction] = (50 kg) a

and

∑ F[perp] = F[normal] + (250 N) sin(-30.0°) - F[weight] = 0

where a is the acceleration of the box. (We ultimately don't care what this acceleration is, though.)

To decide whether the friction here is static or kinetic, consider that when the box is at rest, the net force perpendicular to the floor is

∑ F[perp] = F[normal] - F[weight] = 0

so that, while at rest,

F[normal] = (50 kg) g = 490 N

Then with µ[s] = 0.40, the maximum magnitude of static friction would be

F[s. friction] = 0.40 (490 N) = 196 N

so that the box will begin to slide if it's pushed by a force larger than this.

The horizontal component of our pushing force is

(250 N) cos(-30.0°) ≈ 217 N

so the box will move in our case, and we will have kinetic friction with µ[k] = 0.30.

Solve the ∑ F[perp] = 0 equation for F[normal] :

F[normal] + (250 N) sin(-30.0°) - F[weight] = 0

F[normal] - 125 N - 490 N = 0

F[normal] = 615 N

Then the kinetic friction felt by the box has magnitude

F[k. friction] = 0.30 (615 N) = 184.5 N ≈ 185 N

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2 years ago

In a recent survey, 1358 arizona state university students were asked about their plans after graduation. The following results

lisov135 [29]

The answers to the given questions on the survey of students by the use of a Venn Diagram are;

A) Venn diagram attached

B) 57 Students

C) 811 Students

D) 785 Students

E) 67 Students

<h3>Understanding Venn Diagrams</h3>

We are given;

Total number of Students = 1358

Number of Students that plan to get a new job = 1194

Number of Students that plan to attend graduate school = 306

Number of Students that plan to buy a new car = 547

Number of Students that plan to do all three things = 46

Number of Students that plan to only attend graduate school = 28

Number of Students that plan to get a job and buy a new car, but not attend graduate school = 432

Number of Students that plan to get a new job and attend graduate school = 221

A) I have drawn a Venn Diagram to depict this given numbers of students and I have attached it.

B) From the venn diagram, we can see that the number of people that plan to attend graduate school and buy a new car, but not get a new job = 57

C) From the Venn diagram, we can calculate the number of students that do not plan to buy a new car is;

541 + 175 + 28 + 67 = 811

D) From the venn diagram, we can calculate the number of students plan to get a new job or buy a new car as;

541 + 175 + 12 + 57 = 785

E) From the venn diagram, we can see that the number of students that do not plan to get a new job, attend graduate school, nor buy a new car is; 67

The complete part of the question is;

A) Draw a Venn diagram that represents the situation consisting of 2. cardinalities.

B) How many people plan to attend graduate school and buy a new car, but not get a new job?

C) How many students do not plan a buy a new car?

D) How many students plan to get a new job or buy a new car?

E) How many students do not plan to get a new job, attend graduate school, nor buy a new car?

Read more about Venn Diagrams at; brainly.com/question/2099071

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2 years ago