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3 years ago

8

HELP ME PLEASE!!! Steps would be helpful :)

1 answer:

SIZIF [17.4K]3 years ago

4 0

Answer:

i believe the answer is 9.5

Step-by-step explanation:

cos60 = c / 19 = 9.5

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Prove this trigonometric equation;<br><br> - tan^2x + sec^2x = 1,

alekssr [168]

Hey there :)

- tan²x + sec²x = 1 or 1 + tan²x = sec²x

sin²x + cos²x = 1
Divide the whole by cos²x

$\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}$

$\frac{sinx}{cosx} = tanx$ so $\frac{sin^2x}{cos^2x} = tan^2x$
and
$\frac{1}{cosx} = secx$ so $\frac{1}{cos^2x} = sec^2x$

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0

3 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

3 0

3 years ago

ILL GIVE BRAINLIEST PLS HELP ME

luda_lava [24]

One solution

The two (or more) equations would only intersect once

No solution

Lines never intersect

The lines are parallel

Infinite solutions

The lines are the exact same

That’s all the characteristics I know

3 0

4 years ago

Juanita is a basketball player who makes

Sedaia [141]

Answer: Juanita shoots a series 5 free-throws. Let M = the number of free-throws she makes.

Step-by-step explanation: Khan

6 0

3 years ago

If y = 3x^3 - 2x and dx/dt equals 3, find dy/dt when x = -2. Give only the numerical answer. For example, if dy, dt = 4, type on

Nadya [2.5K]

Answer:

$\frac{dy}{dt} = 102$

Step-by-step explanation:

<u>step(i)</u>

Given function y = 3 x³ - 2 x ... (i)

Differentiating equation (i) with respective to 'x'

$\frac{dy}{dx} = 3 (3 x^{2} ) - 2(1)$

Given x = -2

$(\frac{dy}{dx} ) x_{=-2} = 3 (3 (-2)^{2} ) - 2(1)$

$(\frac{dy}{dx} ) x_{=-2} = 36 -2 =34$

<u><em>Step(ii):-</em></u>

<u><em>we know that </em></u>

$\frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

Given $\frac{dx}{dt} = 3 and \frac{dy}{dx} = 34$

$\frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

substitute values $\frac{dx}{dt} = 3 and \frac{dy}{dx} = 34$

⇒ $34 = \frac{\frac{dy}{dt} }{3 }$

cross multiplication , we get

$\frac{dy}{dt} = 34( 3 ) = 102$

<u><em>Final answer</em></u>:-

$\frac{dy}{dt} = 34( 3 ) = 102$

8 0

3 years ago