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stich3 [128]
3 years ago
9

How much money will you have if you started with $20 and put it in an account that earned 12% every year for 3 years?

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
6 0

Answer:

34,560

Step-by-step explanation:

Started of with 20 and earned 12%  each year.

12% is just 12 as a whole number

so from that 20  12x12x12=1,728

1,728x20=

34.560

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Exponential form of xyyzzz
Trava [24]

Answer:

  xy²z³

Step-by-step explanation:

An exponent is a way to indicate the number of times the factor is repeated. When it is 1, it is rarely shown.

  x is repeated once, so will appear without an exponent

  y is repeated twice, so will have an exponent of 2

  z is repeated 3 times, so will have an exponent of 3

__

  xyyzzz = xy²z³

_____

In plain text, an exponent is indicated with a caret (^).

  xy^2z^3

8 0
3 years ago
A fence must be built to enclose a rectangular area of 20,000 ft^2. Fencing material costs $4 per foot for the two sides facing
Marysya12 [62]

The cost of the least expensive fence is $3200

Step-by-step explanation:

The given is:

  • A fence must be built to enclose a rectangular area of 20,000 ft²
  • Fencing material costs $4 per foot for the two sides facing north and south and ​$8 per foot for the other two sides

We need to find the cost of the least expensive fence

Assume that the length of each side opposite to North or South is x feet and the length of each other sides  is y feet

∵ The length of the rectangle = x feet

∵ The width of the rectangle = y feet

∵ The rectangular area is 20,000 ft²

- Area of a rectangle = length × width

∴ x × y = 20,000

- Divide both sides by x to find y in terms of x

∴ y=\frac{20,000}{x}

The fence's length is equal to the perimeter of the rectangular area

∵ Perimeter of the rectangle = 2 length + 2 width

∴ Perimeter of the rectangle = 2x + 2y

∵ Fencing material costs $4 per foot for the two sides facing

   North and South

∴ x costs $4 per foot

∵ The cost of the other two sides is $8 per foot

∴ y costs $8 per feet

The cost of the fence is the sum of the products of 4 , 2x and 8 , 2y

∵ The cost of the fence (C) = 4(2x) + 8(2y)

∴ C = 8x + 16y

- Substitute y by its value above

∴ C=8x+16(\frac{20,000}{x})

∴ C=8x+\frac{320,000}{x}

To find the least expensive differentiate C with respect to x and equate the answer by 0 to find the value of x

∵ \frac{320,000}{x} can be written as 320,000x^{-1}

∴ C=8x+320,000x^{-1}

∵ \frac{dC}{dx}=8(1)x^{1-1}+320,000(-1)x^{-1-1}

∴ \frac{dC}{dx}=8-320,000x^{-2}

- Equate \frac{dC}{dx} by zero

∴ 8-320,000x^{-2}=0

∵ -320,000x^{-2}=-\frac{320,000}{x^{2}}

∴ 8-\frac{320,000}{x^{2}}=0

- Subtract 8 from both sides

∴ -\frac{320,000}{x^{2}}=-8

- Multiply both sides by x²

∴ - 320,000 = - 8x²

- Divide both sides by -8

∴ 40,000 = x²

- Take √  for both sides

∴ 200 = x

Substitute x in the equation of C to find the least cost of fence

∵ C=8(200)+\frac{320,000}{(200)}

∴ C = 1600 + 1600

∴ C = 3200

The cost of the least expensive fence is $3200

Learn more:

You can learn more about the differentiation in brainly.com/question/4279146

#LearnwithBrainly

5 0
3 years ago
What is the formula of the area of any triangle
MrRissso [65]

Answer:Side x side x side

Step-by-step explanation:

Since it is usually equally sided, it would be SxSxS

4 0
3 years ago
Read 2 more answers
A waffle cone has a height of 7 inches and a diameter of 3 inches. What is the volume of ice cream that can be contained within
Nata [24]

Hey there! I'm happy to help!

To find the volume of a cone, we multiply the base by the height and then divide by three.

First, we find the area of the base, which is a circle. To find a circle, you square the radius and then multiply by pi (or 3.14 in our case).

Radius is half of the diameter.

3/2=1.5

We square this.

1.5²=2.25

We multiply by 3.14

2.25×3.14=7.065

Now, we multiply this base area by the height.

7.065×7=49.455

We divide by 3.

49.455/3=16.485

Therefore, if we round this, our answer is 16.49 in³.

Now you can find the volume of a cone! Have a wonderful day! :D

7 0
3 years ago
If the area around the vegetable garden is of uniform width (labeled with x) and the dimensions of the vegetable garden is 45 fe
Nady [450]
Area of Rectangle = Width × Length

Vegetable Garden
Width = 20
Length = 45
Area of Vegetable Garden = 20×45=900 Sq ft

Area of Entire Garden = Width × Length
Width = 20 + 2x
Length = 45 + 2x
Area = (20 + 2x)(45 + 2x)
(2x + 20)(2x + 45)
4x^2 + 90x + 45x + 900
Area of Entire Garden = 4x^2 + 135x + 900

Area of Flower Garden = Area of Entire Garden - Area of Vegetable Garden

(4x^2 + 135x + 900) - (20 × 45)
4x^2 + 135x + 900 - 900
Area of Flower Garden = 4x^2 + 135x

7 0
3 years ago
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