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solong [7]
2 years ago
7

How to Write 1620 as a product of its prime factors.

Mathematics
2 answers:
natima [27]2 years ago
6 0

Answer:

Step-by-step explanation:

The orange divisor(s) above are the prime factors of the number 1,620. If we put all of it together we have the factors 2 x 2 x 3 x 3 x 3 x 3 x 5 = 1,620. It can also be written in exponential form as 22 x 34 x 51.

Amanda [17]2 years ago
5 0

Answer:

2x2x2x3x3x3x3x5

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Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^5(+3)^0\\
2&+5&(2x)^4(+3)^1\\
3&+10&(2x)^3(+3)^2\\
4&+10&(2x)^2(+3)^3\\
5&+5&(2x)^1(+3)^4\\
6&+1&(2x)^0(+3)^5
\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^4(-3y)^0\\
2&+4&(2x)^3(-3y)^1\\
3&+6&(2x)^2(-3y)^2\\
4&+4&(2x)^1(-3y)^3\\
5&+1&(2x)^0(-3y)^4
\end{array}


\bf (3a+4b)^8\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(3a)^8(+4b)^0\\
2&+8&(3a)^7(+4b)^1\\
3&+28&(3a)^6(+4b)^2\\
4&+56&(3a)^5(+4b)^3\\
5&+70&(3a)^4(+4b)^4\\
6&+56&(3a)^3(+4b)^5\\
7&+28&(3a)^2(+4b)^6\\
8&+8&(3a)^1(+4b)^7\\
9&+1&(3a)^0(+4b)^8
\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
Read 2 more answers
Can someone please please help me. ?????
stira [4]

Answer:

#1

x intercept is -5

y intercept is -5

#2

y=8x

Step-by-step explanation:

6 0
2 years ago
Complete the steps to find the value of x.<br> 2x<br> 1289<br> 22<br> 2
Oksanka [162]

Answer:

Step-by-step explanation:

2x = 128

x = 128/2

x = 64

6 0
3 years ago
Whats the sum of the polynomials (2x3 − 5x − 1) + (4x3 + 8x + 3)
Ipatiy [6.2K]

Answer: 23x

Step-by-step explanation:

5 0
3 years ago
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Evaluate S(3)=10+20log4(3+1)
dimulka [17.4K]
Asssuming you mean

evaluate 10+20log_4(3+1)

remember log_a(a)=1
so
10+20log_4(3+1)=
10+20log_4(4)=
10+20(1)=
10+20=
30
4 0
3 years ago
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