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Daniel [21]
2 years ago
12

Plzz look into the question in the attachements

Mathematics
1 answer:
iren2701 [21]2 years ago
8 0

Given : Diameter of the right circular cone ==> 8 cm

It means : The Radius of the right circular cone is 4 cm (as Radius is half of the Diameter)

Given : Volume of the right circular cone ==> 48π cm³

We know that :

\bigstar \ \ \boxed{\textsf{Volume of a right circular cone is given by : $\pi r^2\dfrac{h}{3}$}}

where : r is the radius of the circular cross-section.

             h is the height of the right circular cone.

Substituting the respective values in the formula, we get :

\mathsf{\implies \pi \times (4)^2 \times \dfrac{h}{3} = 48\pi}

\mathsf{\implies 16 \times \dfrac{h}{3} = 48}

\mathsf{\implies \dfrac{h}{3} = 3}

\implies \boxed{\mathsf{h= 9 \ cm}}

<u>Answer</u> : Height of the given right circular cone is 9 cm

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I need help I don't know how to do this ​
Trava [24]

Answer:

Median = 7

upper quartile = 10

lower quartile is 6

Step-by-step explanation:

The median is the middle line in the box

Median = 7

The upper quartile is the right line of the box

upper quartile = 10

The lower quartile is the left line of the box

lower quartile is 6

4 0
3 years ago
16^10 x 16^4 need the work
Alex787 [66]

Answer:

16^{10}*16^{4}  \\= 16^{14}

Property used: a^{m} * a^{n} = a^{m+n}

3 0
3 years ago
In a fruit punch drink, the 3 ingredients are apple juice, orange juice and cranberry juice. If 2/7 of
Sladkaya [172]

Answer:

3 : 4 : 7

Step-by-step explanation:

apple juice - 2/7 = 4/14

orange juice - 1/2 = 7/14

AJ + OJ = 11/14

this means that 3/14 of the punch is cranberry juice.

cranberry : apple : orange

3 : 4 : 7

8 0
2 years ago
Can anyone help me with this page i can’t find the answers
Dvinal [7]

1) f(x)=2x

when x=3 then f(x) =3×2=<em><u>6</u></em>

when x=4 then f(x)=4×2=<em><u>8</u></em>

2)At y=35(no. of mangoes),x corresponds to y=60(amount)

so$<em><u>6</u></em><em><u>0</u></em><em><u>,</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>he</u></em><em><u> </u></em><em><u>need</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>spend</u></em><em><u>!</u></em>

3) f(x)= x+2

for x=1, f(x)=1+2=<em><u>3</u></em>

for x=2,f(x)=2+2=<em><u>4</u></em>

✌️:)

8 0
3 years ago
Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x
BaLLatris [955]

Answer:

The area of the region is 25,351 units^2.

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em>f<em> is a continuous function on </em>[a,b]<em>, then</em>

                                   \int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) |  {_a^b}

where F is an antiderivative of f.

A function F is an antiderivative of the function f if

                                                    F^{'}(x)=f(x)

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x + 15 and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx

\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2

3 0
3 years ago
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