Question

Plzz look into the question in the attachements

Answer 1

Given : Diameter of the right circular cone ==> 8 cm

It means : The Radius of the right circular cone is 4 cm (as Radius is half of the Diameter)

Given : Volume of the right circular cone ==> 48π cm³

We know that :

$\bigstar \ \ \boxed{\textsf{Volume of a right circular cone is given by : \pi r^2\dfrac{h}{3} }}$

where : r is the radius of the circular cross-section.

             h is the height of the right circular cone.

Substituting the respective values in the formula, we get :

$\mathsf{\implies \pi \times (4)^2 \times \dfrac{h}{3} = 48\pi}$

$\mathsf{\implies 16 \times \dfrac{h}{3} = 48}$

$\mathsf{\implies \dfrac{h}{3} = 3}$

$\implies \boxed{\mathsf{h= 9 \ cm}}$

Answer : Height of the given right circular cone is 9 cm