2 years ago

The sum of 6 consecutive integers is 387. What is the sixth term in the sequence

2 answers:

8 0

We'll call our first integer n. Since the six integers are consecutive, we have:

$n+(n+1)+(n+2)+(n+3)+(n+4)+(n+5)+(n+6)=387$
$6n+21=387$
$6n=366$
$n=61$

So the first integer is 61. Then the sixth integer would be 67, since it's just the first plus six.

MAXImum [283]2 years ago

4 0

62,63,64,65,66,67
6th term:67

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