Step-by-step explanation:
From Trig
1 + tan²x = Sec²x
Also
Sec²x = 1/cos²x
Now
Cot²x = 1/tan²x = cos²x/sin²x
Putting all together
Cot²x(1+tan²x)
= Cot²x(sec²x)
= cos²x/sin²x(1/cos²x)
cos²x on the numerator and that one the denominator cancels out
we have
= 1/sin²x
From Trig
1/sin²x = cosec²x
So Our Answer = cosec²x.
-4(4x+3) + (7x -2) = (-16x + -12) + (7x + 2) = -16 + -12 + 7x + 2 = -9x -10
The answer is -9x -10
[2,INFINITY SIGN)
{y|y greater than and equal to 2}
i hope it helps
