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4 years ago

10

Can anyone help with polynomials?

1 answer:

Evgen [1.6K]4 years ago

6 0

Yes. I can help. What do you need with help with concerning polynomials?

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Help me figure this out.

sleet_krkn [62]

Let me help you,
For this question, you should know that 2 2/4 is equal to 10/4.
So we know that 10/4 is 10 times 1/4.
If Julie has 1/4-cup measuring cup, then she should use her cup 10 times to get 2 2/4 cups of raisins.
Have a good one!

5 0

4 years ago

Help me class8 (surds)

Mashcka [7]

Answer:

$\cfrac{991\sqrt{2} }{80}$

Step-by-step explanation:

For a start simplify each of the roots:

$\sqrt{72} =\sqrt{36*2} =6\sqrt{2}$
$\sqrt{50} =\sqrt{25*2} =5\sqrt{2}$
$\sqrt{128} =\sqrt{64*2} =8\sqrt{2}$
$\sqrt{98} =\sqrt{49*2} =7\sqrt{2}$

Now simplify the expression in steps:

$\sqrt{72}-\cfrac{48}{\sqrt{50} } -\cfrac{45}{\sqrt{128} } +2\sqrt{98} =$

$6\sqrt{2}-\cfrac{48}{5\sqrt{2} } -\cfrac{45}{8\sqrt{2} } +2*7\sqrt{2} =$

$6\sqrt{2}-\cfrac{48*8+45*5}{5*8\sqrt{2} } +14\sqrt{2} =$

$20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =$

$\sqrt{2} (20-7\cfrac{49}{80} )=$

$\sqrt{2} *12\cfrac{31}{80} =$

$\cfrac{991\sqrt{2} }{80}$

3 0

2 years ago

Whats 58788188 to the nearest million

In-s [12.5K]

Answer:

588,000,000.

Step-by-step explanation:

Inserting commas every 3 digits from the right, we have:

587,881,188 so that is 587 million and 881,000.

As 8 is the next digit after the 587 we add 1 to 587 to make 588 million.

7 0

3 years ago

If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2

kramer

Answer:

6

Step-by-step explanation:

Here it's given that ,

$\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}$

Also ,

$\sf\red{\longrightarrow} s =\dfrac{a+b+c}{2}$

And we need to find out the value of A , when

a = 3
b = 4
c = 5

So , on substituting the respective values to find s we have ,

$\sf\red{\longrightarrow} s =\dfrac{3+4+5}{2}=\dfrac{12}{2}=\bf{6}$

Now let's find out A as ,

$\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)} \\$

$\sf\red{\longrightarrow}A =\sqrt{6 * 3 * 2 * 1}\\$

$\sf\red{\longrightarrow} A = \sqrt{3^2 * 2^2 *1^2}\\$

$\sf\red{\longrightarrow}A = 3*2\\$

$\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}$

7 0

2 years ago

Need answer asap, correct answer gets brainliest.

garik1379 [7]

Answer:

A is (6,-4)

Step-by-step explanation:

5 0

3 years ago