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balandron [24]
3 years ago
10

Students were surveyed about their favorite colors. 1/4 of the students preffered red, 1/8 of the students preffed blue, and 3/5

of the remaining students prefeered green. If 15 students preferred green, how many students were surveyed?
Mathematics
1 answer:
lapo4ka [179]3 years ago
8 0
27 is how much kids did the survey because I added all the fractions together like how the question did 3/5 which is 3 × 5 = 15
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A sales person earns a commission based on the number and type of vehicle sold. A person selling 6 cars and 3 trucks earns 4,800
AURORKA [14]
Assign variables to you unknowns.

c = $ cars
t = $ trucks

6c + 3t = 4800
8c + t = 4600

use substitution or elimination to solve the system of equations.

using elimination.. multiply second equation by -3 and add to the other to combine equations into one.

6c + 3t = 4800
-3(8c + t = 4600)
---------------------------
-18c + 0 = -9000
c = 9000/18
c = 500 $

use this in one of the equations to find the cost of a truck.

8(500) + t = 4600
4000 + t = 4600
t = 4600 - 4000
t = 600 $

question asks
2(500) + 3(600) =
1000 + 1800 = 2800 $
3 0
3 years ago
How do you find area and perimeter of a rectangle with the side lengths of 5x^2 and 12x?
valentinak56 [21]

Answer:

The area can be found by multiplying the two terms, and the perimeter by doubling and adding them.

Using this, we find that the area of the rectangle is 60x³, and the perimeter is 10x² + 24x.

Step-by-step explanation:

First let's find the area:

5x² × 12x

= 60x³

Now the perimeter:

2(5x² + 12x)

= 10x² + 24x

8 0
3 years ago
Can any help me with this question
Y_Kistochka [10]
Ok...there are 6 days in the week that end in a y: Monday, Wednesday, Thursday, Friday, Saturday, Sunday.
Saturday is one out of the 6, so it's 1/6....If they want it as a percent, then divide 1 by 6, and multiply it by 100.

Hope I helped!
4 0
3 years ago
What is another to describe an equilateral triangle . PICK BELOW
krok68 [10]
The answer is a right triangle meaning that all sides and angles are equal.
7 0
3 years ago
Read 2 more answers
Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0
Leokris [45]

Substitute v(x)=-2x+y(x), so that \dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}. Then the ODE is equivalent to

\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7

which is separable as

\dfrac{\mathrm dv}{v^2-9}=\mathrm dx

Split the left side into partial fractions,

\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)

so that integrating both sides is trivial and we get

\dfrac{\ln|v-3|-\ln|v+3|}6=x+C

\ln\left|\dfrac{v-3}{v+3}\right|=6x+C

\dfrac{v-3}{v+3}=Ce^{6x}

\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}

\dfrac6{v+3}=1-Ce^{6x}

v=\dfrac6{1-Ce^{6x}}-3

-2x+y=\dfrac6{1-Ce^{6x}}-3

y=2x+\dfrac6{1-Ce^{6x}}-3

Given the initial condition y(0)=0, we find

0=\dfrac6{1-C}-3\implies C=-1

so that the ODE has the particular solution,

\boxed{y=2x+\dfrac6{1+e^{6x}}-3}

5 0
3 years ago
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