Question

A(-2,3)

Answer 1

Answer:

The perimeter of triangle is 19.8 units

Step-by-step explanation:

we know that

The perimeter of triangle ABC is

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

we have

$A(-2,3),B(3,0)$

substitute in the formula

$d=\sqrt{(0-3)^{2}+(3+2)^{2}}$

$d=\sqrt{(-3)^{2}+(5)^{2}}$

$d_A_B=\sqrt{34}\ units$

step 2

Find the distance BC

we have

$B(3,0),C (-4,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(-4-3)^{2}}$

$d=\sqrt{(-3)^{2}+(-7)^{2}}$

$d_B_C=\sqrt{58}\ units$

step 3

Find the distance AC

we have

$A(-2,3),C (-4,-3)$

substitute in the formula

$d=\sqrt{(-3-3)^{2}+(-4+2)^{2}}$

$d=\sqrt{(-6)^{2}+(-2)^{2}}$

$d_A_C=\sqrt{40}\ units$

step 4

Find the perimeter

$P=AB+BC+AC$

substitute the values

$P=\sqrt{34}+\sqrt{58}+\sqrt{40}$

$P=19.8\ units$