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julia-pushkina [17]
3 years ago
13

Multiply the polynomials (x + 3) (2x - 4). What is the product in the form ax2 + bx + c? Enter your answers in the boxes.

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0
The answer is 2x2+2x-12
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136 days to 85 days<br><br> Please help
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How do you solve 32 - 6x = 53?
katrin2010 [14]

\large\boxed{x=-\frac{7}{2}}

To solve for x, we need to isolate it on one side of the equation.

The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.

Subtract 32 from both sides of the equation.

\begin{aligned}32-32-6x&=53-32\\-6x&=21\end{aligned}

Divide both sides of the equation by -6.

\begin{aligned}\frac{-6x}{-6}&=\frac{21}{-6}\\x&=\boxed{-\frac{7}{2}}\end{aligned}

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2 years ago
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Kevin M. walks 3 blocks south from his home to school, &amp; Phenix walks 2 blocks north from 50 points her home to Kevin's home
mariarad [96]

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2+2 is 4 minus one thats 3 quick math, everyday men on the block smo** trees, see yo girl in da park dat gurl was an ocus, n the ting went ggggrrraaa paa paa paa paa paa grrrrrraaa n a boom boom boom boom boom!!!!!

Step-by-step explanation:

4 0
3 years ago
Write the values in the boxes that make the statement true
nikklg [1K]

Answer:

  • \frac{5}{3}xz^8*9x^6y^0z^2 = 15x^7z^{10}

Step-by-step explanation:

<u>Given</u>

  • \frac{5}{3}xz^a*bx^cy^dz^2 = 15x^7z^{10}

<u>Simplify</u>

  • \frac{5}{3}b*x^{1+c}z^{a+2}y^d = 15x^7z^{10}y^0

Compare left and right sides and

<u>Find b:</u>

  • <u />\frac{5}{3} b = 15 ⇒ b = 15*3/5 = 9

<u>Find c:</u>

  • 1 + c = 7 ⇒ c = 7 - 1 = 6

<u>Find a:</u>

  • a + 2 = 10 ⇒ a = 10 - 2 = 8

<u>Find d:</u>

  • d = 0

<u>Solution is:</u>

  • \frac{5}{3}xz^8*9x^6y^0z^2 = 15x^7z^{10}
8 0
3 years ago
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