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svlad2 [7]
2 years ago
11

Use the discriminant to determine the kinds of numbers that satisfy the equation 5x = x² - 3. Do not solve.

Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
5 0
Kakakakakakakakakakakakakskak
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Log7 (4n-7)=log7 (-3n )
arsen [322]
4n-7=-3n
add 3n to both sides
and then solve for n
n=1
5 0
3 years ago
Can y’all help me on this graph work asap pls
Alenkasestr [34]

Answer:i know it its 8 sorry

Step-by-step explanation:

7 0
2 years ago
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Can you please answer this question
tamaranim1 [39]
3tan^{2} \theta +7sec\theta=3
First I converted the equation terms into sine and cosine.
tan^{2}\theta = \frac{sin^{2}\theta}{cos^{2}\theta} and sec\theta= \frac{1}{cos\theta}
Substitution:
\frac{3sin^2\theta}{cos^2\theta} + \frac{7}{cos\theta} =3
Common Denominator Created:
\frac{3sin^2\theta}{cos^2\theta} + \frac{7cos\theta}{cos^2\theta} =3
Multiply each term by the LCD:
3sin^2\theta+7cos\theta=3cos^2\theta
Substitution: Recall ⇒sin^2\theta =1-cos^2\theta 
3(1-cos^2\theta)+7cos\theta=3cos^2\theta
Distribute and collect all terms on one side:
6cos^2\theta-7cos\theta-3=0
Factor and set each factor equal to 0:
(2cos\theta-3)(3cos\theta+1)=0
2cos\theta-3=0⇒theta=cos^{-1} \frac{3}{2}
3cos\theta+1=0⇒theta=cos^{-1} \frac{-1}{3}
The 2nd factor provides only possible answer 109.5 degrees

4 0
3 years ago
Multiply:4x^3sqrt4x^2(2^3sqrt32x^2-x^3sqrt2x)
larisa [96]

8x^5\left(32\sqrt{2}x^2-\sqrt{2}x^4\right)

7 0
3 years ago
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PLEASE HELP THANK YOU!
Vsevolod [243]

Answer:

um wow that is realy hard

Step-by-step explanation:

8 0
3 years ago
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