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3 years ago

50 points. Please quick.

Mathematics

1 answer:

Allisa [31]3 years ago

3 0

Answer:

Condition A.

A rectangle with four right angles

There can be many quadrilaterals satisfying this condition.

Condition B.

A square with one side measuring 5 inches

There can be only one quadrilateral satisfying this condition.

Condition C.

A rhombus with one angle measuring 43°

There can be many quadrilaterals satisfying this condition.

Condition D.

A parallelogram with one angle measuring 32°

There can be many quadrilaterals satisfying this condition.

Condition E.

A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.

There can be only one quadrilateral satisfying this condition.

Condition F.

A rectangle with adjacent sides measuring 4 inches and 3 inches.

There can be only one quadrilateral satisfying this condition

Step-by-step explanation:

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Answer:

a) Given expression,

12% of 312

Since 100% of 312 = 312

⇒ 10% of 312 = 31.2,

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So, 12% of 312 = 10% of 312 + 2% of 312

= 31.2 + 6.24

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b) Given,

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A tester sets 99% confidence limits on a certain statistic. The absolute difference between either limit and the mean is an exam

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Answer:

(Choice A)

Juanita gets a strike next game.'

Step-by-step explanation:

Your question is obviously incomplete.

Complete question is:

Juanita and Nina are bowling together. The probability of Juanita getting a strike next game is 24%. The probability of Nina getting a strike next game is 0.17. Which of these events is more likely?

(Choice A)

Juanita gets a strike next game.'

(Choice B)

Nina gets a strike next game.

(Choice C)

Neither. Both events are equally likely.

Answer:

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probability of Nina getting a strike next game: P(N) = 0.17

As you can see 0.24 > 0.17 ----> P(J)>P(N)

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