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3 years ago

50 points. Please quick.

Mathematics

1 answer:

Allisa [31]3 years ago

3 0

Answer:

Condition A.

A rectangle with four right angles

There can be many quadrilaterals satisfying this condition.

Condition B.

A square with one side measuring 5 inches

There can be only one quadrilateral satisfying this condition.

Condition C.

A rhombus with one angle measuring 43°

There can be many quadrilaterals satisfying this condition.

Condition D.

A parallelogram with one angle measuring 32°

There can be many quadrilaterals satisfying this condition.

Condition E.

A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.

There can be only one quadrilateral satisfying this condition.

Condition F.

A rectangle with adjacent sides measuring 4 inches and 3 inches.

There can be only one quadrilateral satisfying this condition

Step-by-step explanation:

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A crew will arrive in one week and begin filming a city for a movie. The mayor is desperate to clean the city streets before fil

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Step-by-step explanation:

1 week = 7 days of 24 hours each = 7×24 = 168 hours.

the first team can do 1/700 of the total work per hour.

the second team can do 1/600 if the total work per hour.

if they work together, then 1/700 + 1/600 of the total work can be done per hour.

to add these 2 fractions we need to bring them to the same denominator. and that would be 4200 (LCM of 700 and 600).

1/700 + 1/600 = 6/4200 + 7/4200 = 13/4200

so, together, they can do 13/4200 if the total job in 1 hour.

how many hours will they need together to finish the job ?

well, how often does 13 fit into 4200 (as 4200/4200 is the complete job) ?

4200 / 13 = 323.0769231... hours

so, it will still take a little bit over 323 hours to clean all the streets.

but there are only 168 hours until the film crew starts.

so, no, there is not enough time.

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2 years ago

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3 years ago

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dolphi86 [110]

Answer:

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Step-by-step explanation:

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prove that sin theta cos theta = cot theta is not a trigonometric identity by producing a counterexample

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Answer:

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Begin with the right hand side:

R.H.S = cot θ = $\frac{cos \ \theta}{sin \ \theta}$

L.H.S = sin θ cos θ

so, sin θ cos θ ≠ $\frac{cos \ \theta}{sin \ \theta}$

So, the equation is not a trigonometric identity.

=========================================================

<u>Anther solution:</u>

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Assume θ with a value and substitute with it.

Let θ = 45°

So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2

R.H.S = cot θ = cot 45 = 1

So, L.H.S ≠ R.H.S

So, sin θ cos θ = cot θ is not a trigonometric identity.

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3 years ago

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