Answer:
Step-by-step explanation:
Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:
First airplane
Where t is the time measured in hours.
Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:
Rate of change of such distance can be found by the deriving the expression in terms of time:
Where 
and 
, respectively. Distances of each airliner at 2:30 PM are:
The rate of change is:
<span>50+<span>24<span>6<span>x2
</span></span></span></span><span>=<span><span><span>300<span>x^2</span></span>+24/</span><span>6<span>x^2
the answer is </span></span></span></span><span>=<span><span><span>50<span>x^2</span></span>+4/</span><span>x^<span>2</span></span></span></span>
Answer:
no solution exists:
Step-by-step explanation:
x²−1x+10=0
Step 1: Simplify both sides of the equation.
x²−x+10=0
Step 2: Subtract 10 from both sides.
x²−x+10−10=0−10
x²−x=−10
Step 3: The coefficient of -x is -1. Let b=-1.
Then we need to add (b/2)^2=1/4 to both sides to complete the square.
Add 1/4 to both sides.
x²−x+
1/4=−10+
1/4
x²−x+
1/4=−39
/4
Step 4: Factor left side.
(x -1/2)² = −39
/4
Step 5: Take square root.
x −1
/2 =±√
−39
/4
Step 6: Add 1/2 to both sides.
x =−1/2 + 1/2 = 1/2 ±√
-39/4
x = 1/2 ±√
-39/4
No real solutions.
Answer:
y = 1
Step-by-step explanation:
