Question:
At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent decrease of water in the tank
Answer:
The percent Decrease of water in the tank is 50%
Step-by-step explanation:
Given:
Initial amount of water in the tank at the noon = 6 cm
amount of water remained in water after several hours = 3 cm
To Find:
The percent decrease =?
Solution:
The percent decrease in the tank
=>
Substituting the values
=>
=>
=>
=> 50
Answer:
= 3 3/4 m^2
or 15/4 m^2
Step-by-step explanation:
The base is the triangle.
A =1/2 bh
A = 1/2 (3 1/3 * 9/4)
Change 3 1/3 to an improper fraction (3*3+1)/3 = 10/3
A = 1/2 * 10/3 *9/4
Re arranging
= 1/2* 9/3 * 10/4
= 1/2 (3) 5/2
=15/4
Now writing as a mixed number
= 3 3/4 m^2
24.12 I did 180% times 13.4
in this one x=9 ask if you need an explanation
Well you would have to put 25 make in between 1,4, -2