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jonny [76]
3 years ago
6

Why is 0.03 less than 7.85?

Mathematics
1 answer:
IRINA_888 [86]3 years ago
7 0
I think 0.3 is less 7.85 because there is a 1 on the end that was is a 3 and if you round it would be 0
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A group of students is collecting books to add to their librarby. The table shows the number of books in the librarby after 1, 3
Grace [21]

Answer:

(7,48)

Step-by-step explanation

the books go up by ten  and the days go up by 2

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A triangle has side lengths of 24 in., 32 in., and 40 in. Is the triangle acute, obtuse, or right? A) right. B) obtuse. C) acute
Feliz [49]
24,  32 ,  40.           Divide through by 8

3,    4,    5,            

The 3 , 4, 5 reminds of the Pythagorean triple, which is a right angled triangle.

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I need help with this question.
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What is 1 2/5 × 2<br>what is 1/4 × 1​
Mrrafil [7]

Answer:

1).  2\frac{4}{5}

2).  \frac{1}{4}

Step-by-step explanation:

1). 1\frac{2}{5}*2

Convert mixed number to improper fraction: a\frac{b}{c} =\frac{a*c+b}{c}

1\frac{x2}{5} =\frac{1*5+2}{5} =\frac{7}{5}

\frac{7}{5} *2

\frac{7}{5} *2

Apply the fraction rule: \frac{a}{b}*c =\frac{a*c}{b}

\frac{7}{5} *2=\frac{7*2}{5}

=\frac{7*2}{5}

Multiply the numbers: 7*2=14

=\frac{14}{5}

Convert improper fractions to mixed numbers: \frac{14}{5}

\frac{14}{5}

Write the problem in long division format:

\begin{matrix}5\overline{|\smallspace14}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}

Divide 14 by 5 to get 2

\begin{matrix}\space\space\space\space\space\space\emptyspace2\space\space\space\space\space\space\space\space\space\space\space\space\\ 5\overline{|\smallspace14}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}

Multiply the quotient digit (2) by the divisor 5

\begin{matrix}\space\space\space\space\space\space\emptyspace2\space\space\space\space\space\space\space\space\space\space\space\space\\ 5\overline{|\smallspace14}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace1\emptyspace0}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}

Subtract 10 from 14

\begin{matrix}\space\space\space\space\space\space\emptyspace2\space\space\space\space\space\space\space\space\space\space\space\space\\ 5\overline{|\smallspace14}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace1\emptyspace0}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\space\space\emptyspace4\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}

The solution for long division of \frac{14}{5} is 2 with a remainder of 4

2\quad \mathrm{Remainder}\quad \:4

Convert to mixed number: Quotient\frac{Remainder}{Divisor}

\frac{14}{5} =2\frac{4}{5}

=2\frac{4}{5}

2\frac{4}{5}

Convert \frac{4}{5} to decimal using long division

\frac{4}{5}

Divide 4 by 5 to get 0

\begin{matrix}\space\space\space\space\emptyspace0\space\space\space\space\space\space\space\space\space\space\space\space\\ 5\overline{|\smallspace4}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}

Multiply the quotient digit (0) by the divisor 5

\begin{matrix}\space\space\space\space\emptyspace0\space\space\space\space\space\space\space\space\space\space\space\space\\ 5\overline{|\smallspace4}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace0}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}

Subtract 0 from 4

\begin{matrix}\space\space\space\space\emptyspace0\space\space\space\space\space\space\space\space\space\space\space\space\\ 5\overline{|\smallspace4}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace0}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\emptyspace4\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}

Add a decimal place and a zero to the dividend

Bring down the zero from the dividend

\begin{matrix}\space\space\space\space\emptyspace0.\space\space\space\space\space\space\space\space\space\space\space\\ 5\overline{|\smallspace4.0}\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\underline{\emptyspace0}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\emptyspace4\emptyspace0\space\space\space\space\space\space\space\space\space\space\end{matrix}

Divide 40 by 5 to get 8

\frac{40}{5} =8

The solution for long division of \frac{4}{5} is 0.8

=2+0.8

Add 2+0.8=2.8

2). \frac{1}{4} *1

Multiply \frac{1}{4} *1=\frac{1}{4}

=\frac{1}{4}

Anything multiplied by 1 is the same number.

Divide the the numbers \frac{1}{4} to get decimal form

Divide 1 by 4

\frac{1}{4} =0.25

=0.25

8 0
3 years ago
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25 pnts ‼️‼️theres a picture for these. One would help Please need help due in two days forever ‼️‼️
ad-work [718]

There are a lot of math questions here. I'll answer the first 5 questions to get you started.

=============================

Problem 19

This is a permutation because order matters and we want to find out the number of ways to arrange the people in the first, second, third and fourth place slots.

You would use the nPr formula.

=============================

Problem 20

We use the counting principle here. This is because we can create a tree diagram. To find the number of branches in this diagram, you would multiply out all the values.

==============================

Problem 21

This is similar to problem 19; however, order doesnt matter in this case. All that matters is the grouping of books. For example, the group {A,B,C} is the same as {B,C,A} because both groups have the same books in them and the the groups have the same number of books. So in short, we use a combination here instead of a permutation.

You would use the nCr formula.

==============================

Problem 22

Similar to problem 21. Order does not matter so we use a combination. There is no natural way to order or rank the patients being tested, and there's no need to do so, because all that matters is the group itself rather than specific individuals.

==============================

Problem 23

Again, order doesn't matter because we arent worried about rank or position. All we care about is the group. We use a combination here as well.

3 0
3 years ago
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