3 years ago

PLEASE HELP! Trigonometry question :(

1 answer:

4 0

Answer:

see explanation

Step-by-step explanation:

Using the sine ratio

sinA = $\frac{opposite}{hypotenuse}$ = $\frac{k}{c}$

sinC = $\frac{opposite}{hypotenuse}$ = $\frac{k}{a}$

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