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erica [24]
3 years ago
10

Students in band are selling oranges and grapefruit to earn money for a trip. Mrs.Whitten purchased three boxes of oranges and t

wo boxes of grapefruit from a student for a total of $22.50. Mr. Rutig purchased one bag of oranges and four boxes of grapefruit, spending a total of $28.50. How much is one box of oranges?
Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

The cost of one box of oranges = $3.3

Step-by-step explanation:

Let x be cost of one box of oranges and y be the cost of one box of grapefruit.

We have been given that Mrs. Whitten purchased 3 boxes of oranges and 2 boxes of grapefruit from a student for a total of $22.50. We can represent this information as:

3x+2y=22.50...(1)  

Mr. Rutig purchased 1 box of oranges and four boxes of grapefruit, spending a total of $28.50. We can represent this information as:

x+4y=28.50...(2)

We will solve our system of linear equations using substitution method.

From equation (1) we will get,

y=\frac{22.50-3x}{2}

Substituting y's value in equation (2) we will get,

x+4*(\frac{22.50-3x}{2})=28.50

x+2*(22.50-3x)=28.50

Upon distributing 2 we will get,

x+45-6x=28.50

x-6x=28.50-45

-5x=-16.5

x=\frac{-16.5}{-5}

x=3.3

Therefore, the cost of one box of oranges is $3.3.

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Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when M = 0.06, \sigma = 1.1

0.06 = 2.575*\frac{1.1}{\sqrt{n}}

0.06\sqrt{n} = 2.575*1.1

\sqrt{n} = \frac{2.575*1.1}{0.06}

(\sqrt{n})^{2} = (\frac{2.575*1.1}{0.06})^{2}

n = 2228.6

Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

7 0
3 years ago
Which of the following could be the lenght of the sides of a 30 -60 -90 degree triangle
cupoosta [38]
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The long side needs to be x radical 3, the short leg is just x, and the hypotenuse is 2x. So one example could be 5 radical 3, 5, and 5 times 2
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3 years ago
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Imagine the path of the tip of the pendulum as an arc of a circle. The circle would have a radius of 4 feet and the arc would be 20 degrees. To calculate the length of the arc, you need to find 20 degrees of the circumference. 

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5 0
4 years ago
I need help with this one asap please and thank you
inna [77]

Answer:

C

Step-by-step explanation:

A

(m² - 3m + 2) / (m² - m)

we see due to a little bit of experience with expressions and multiplications of expressions that

(m² - 3m + 2) = (m - 2)(m - 1)

(m² - m) = m(m - 1)

so,

(m - 2)(m - 1) / (m(m - 1)) = (m - 2) / m

so, that's not it.

B

(m² - 2m + 1) / (m - 1)

we see again

(m² - 2m + 1) = (m - 1)(m - 1)

so,

(m - 1)(m - 1) / (m - 1) = m - 1

so, that's not it.

C

(m² - m - 2) / (m² - 1)

we see again

(m² - m - 2) = (m - 2)(m + 1)

and

(m² - 1) = (m + 1)(m - 1)

so,

(m - 2)(m + 1) / ((m + 1)(m - 1)) = (m - 2) / (m - 1)

yes, that is the solution.

D

(2m² - 4m) / (2(m - 2))

2m(m - 2) / (2(m - 2)) = 2m/2 = m

no, that is not a solution.

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hence , value of x = 6°

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2 years ago
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