<span>2x/4x+2 x 14 x+7/6 is unclear. Do you mean 2/4x, or do you mean 2x
-------- ??
4x+2
Use parentheses to make things clearer.
I will assume that you meant to write
2x
--------- * 14x + 7/6
4x + 2
but am very much unsure if this is correct or not.
Perhaps you meant
</span>2x/(4x+2) times 14(x+7/6)
<span>
This comes out as follows:
2x * 14 (x + 7/6) 28x(x + 7/6) 14x(x + 7/6)
------------------------ = ------------------- = --------------------
4x+2 2(2x + 1) 2x + 1 after reduction.
Performing the multiplication, we get 14x^2 + 98/6
--------------------
2x+1
</span>
It appears that you're using "x" both as a variable name and as the "multiply" operator. If so, please don't! Use " * " to indicate multiplication.
<span>
</span>Please take and share a screen shot of this problem.
Answer:
D-Spinning a spinner with 4 equal sections, where 3 out of 4 sections represent students who drove themselves to school.
Step-by-step explanation:
75% = 3/4
Answer:
Step-by-step explanation:
<u>a)</u>
- Given that ; X ~ N ( µ = 65 , σ = 4 )
From application of normal distribution ;
- Z = ( X - µ ) / σ, Z = ( 64 - 65 ) / 4, Z = -0.25
- Z = ( 66 - 65 ) / 4, Z = 0.25
Hence, P ( -0.25 < Z < 0.25 ) = P ( 64 < X < 66 ) = P ( Z < 0.25 ) - P ( Z < -0.25 ) P ( 64 < X < 66 ) = 0.5987 - 0.4013
- P ( 64 < X < 66 ) = 0.1974
b) X ~ N ( µ = 65 , σ = 4 )
From normal distribution application ;
- Z = ( X - µ ) / ( σ / √(n)), plugging in the values,
- Z = ( 64 - 65 ) / ( 4 / √(12)) = Z = -0.866
- Z = ( 66 - 65 ) / ( 4 / √(12)) = Z = 0.866
P ( -0.87 < Z < 0.87 )
- P ( 64 < X < 66 ) = P ( Z < 0.87 ) - P ( Z < -0.87 )
- P ( 64 < X < 66 ) = 0.8068 - 0.1932
- P ( 64 < X < 66 ) = 0.6135
c) From the values gotten for (a) and (b), it is indicative that the probability in part (b) is much higher because the standard deviation is smaller for the x distribution.
Answer:
The 99% confidence interval for the mean amount of money spent on lunch per week for all college students is between $41.40 and $44.60.
Step-by-step explanation:
A confidence interval has two bounds, a lower bounds and an upper bound.
These bounds depend on the sample mean and the margin of error.
The lower bound is the sample mean subtracted by the margin of error.
The upper bound is the margin of error added to the sample mean.
In this problem, we have that:
The sample mean is $43.
The margin of error is $1.60 for a 99% confidence interval.
Lower bound: 43 - 1.60 = $41.40
Upper bound: 43 + 1.60 = $44.60
The 99% confidence interval for the mean amount of money spent on lunch per week for all college students is between $41.40 and $44.60.
Your Answer is C bud There ya go
