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a_sh-v [17]
3 years ago
8

Which statements about the hyperbola are accurate?

Mathematics
1 answer:
Marysya12 [62]3 years ago
3 0

Answer:

A. There is a focus at (-9, 1).

D. There is a directrix at x = -5.8.

F. There is a directrix at x = -2.2.

Step-by-step explanation:

Just did it in edg

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3/4 pounds make how many oz?
IRISSAK [1]

Answer:

12

Step-by-step explanation:

5 0
2 years ago
Help binomial distributions
Ymorist [56]

We have the formula to compute the probability of having exactly k successed over n trials, given a probability p of success (and implicitly a probability 1-p of failure), which is


P(\text{k successed on n trials}) = \binom{n}{k}p^k(1-p)^{n-k}


Now, the probability of at least 3 successes is the union of the following event: exactly three successes,exactly four successes and exactly five successes.


We can compute their probability and sum them:\binom{5}{3}\left(\frac{3}{7}\right)^3\left(\frac{4}{7}\right)^2 + \binom{5}{4}\left(\frac{3}{7}\right)^4\left(\frac{4}{7}\right)^1 + \binom{5}{5}\left(\frac{3}{7}\right)^5 \approx 0.36788


So, the answer is about 36.79%

3 0
3 years ago
What is the average mass of all four inner planets in scientific notation in scientific notation
Snezhnost [94]
2,953.54 * 10^21 kg

https://www.quora.com/What-is-the-average-mass-of-the-rocky-planets-in-our-solar-system
6 0
3 years ago
A parallelogram has an area of 125 square inches. If it is
elena-14-01-66 [18.8K]

L x W = A

25 x W = 125

So now you dived 125 by 25

125 ÷ 25 = 5

7 0
2 years ago
Two baseball players bat first and second in the lineup. The first batter has an on-base percentage of 0.23. The second batter h
irina1246 [14]

Answer:

The probability that neither player gets on base is 0.4824

Step-by-step explanation:

1. Both players get to base. <em>Just multiply the two probabilities together</em>:

= (<em>probability first batter gets on base</em>) x (<em>probability second batter gets on base, if the first batter gets on base</em>)

= 0.23 x 0.38

= 0.0874

2. One player gets to base. The formula here is P(A+B) =P(A) + P(B) - P(A) x P(B)

= (<em>probability first batter gets on base</em>) + (<em>probability second batter gets on base, if the first batter does not</em>) - (0.23 x 0.26)

= 0.23 + 0.26 - (0.23 x 0.26)

= 0.49 - 0.0598

= 0.4302

3. Neither player gets to base =<em> 1 - addition of the previous two cases</em>.

= 1 - (0.0874 + 0.4302)

= 1 - 0.5176

= 0.4824

7 0
3 years ago
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