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a_sh-v [17]
3 years ago
8

Which statements about the hyperbola are accurate?

Mathematics
1 answer:
Marysya12 [62]3 years ago
3 0

Answer:

A. There is a focus at (-9, 1).

D. There is a directrix at x = -5.8.

F. There is a directrix at x = -2.2.

Step-by-step explanation:

Just did it in edg

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PLEASE HELP PLEASE!!!!!!!
dybincka [34]

Answer:

step 1, he needed to add 2b to both sides

Step-by-step explanation:

he needed to do this to get rid of that 2b

6 0
3 years ago
A circle with a radius of one unit is inscribed in an equilateral triangle with an area of 4√3 square units. Determine the exact
chubhunter [2.5K]

Answer:

4√3 -π square units

Step-by-step explanation:

The triangle area is given. The area of the circle is πr², where r=1, so is π square units.

If the shaded area is the difference, then its area is ...

... 4√3 - π

_____

<em>Comment on the problem statement</em>

Normally, when a figure is "inscribed", the size of the inscribed figure is limited by the enclosing figure. Here, the circle is not "inscribed" in the triangle, as the triangle is larger than would be required for an inscribed circle of radius 1.

7 0
4 years ago
Ten calculators cost $149.50. How much would 100 cost? 1000? 500?
professor190 [17]

Answer:

for 100 it will be $149,500

Step-by-step explanation:

3 0
3 years ago
Write 10x+2y=4 in function notation
vlada-n [284]

Firstly, get it into y=mx+b form

Subtract 10x

2y=-10x+4

Divide by 2

y=-5x+2

Change y to f(x) to make it into function notation

f(x)=-5x+2

4 0
3 years ago
Read 2 more answers
Bubble wrap sells in sheets, and each sheet has 1 million individual spherical bubbles, each with a diameter of 0.01 m. What is
Triss [41]

Answer: The total volume of air contained in the bubbles of one sheet of bubble wrap is about 0.5 cubic meters.

Step-by-step explanation:

Volume of sphere :-

V=\dfrac{4}{3}\pi r^3, where r is the radius of the sphere.

Given : Diameter of the bubble = 0.01 m

Then Radius of the bubble = \dfrac{0.01}{2}=0.005\ m

Volume of each bubble:-

V=\dfrac{4}{3}(3.14) (0.005)^3

Also, Number of bubbles in each sheet = 1,000,000

Then , the total volume of air contained in the bubbles of one sheet of bubble wrap will be :-

\dfrac{4}{3}(3.14) (0.005)^3\times1,000,000=0.52333333\approx0.5\ \text{cubic meters}

Hence, the total volume of air contained in the bubbles of one sheet of bubble wrap is about 0.5 cubic meters.

5 0
3 years ago
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