What’s the answer to this ?

Suzy fills a 1 pint thermos with milk each day for lunch how many times will she be able to fill her thermos with 1/2 gallon of

pogonyaev

1 gallon is 8 pints....so 1/2 gallon = 4 pints

she fills a 1 pt thermos with milk each day......how many times will she be able to fill her thermos with 1/2 gallon (or 4 pints) of milk ?

if she fills a 1 pint thermos each day....and she has 4 pints of milk, then she will be able to fill her thermos 4 times <===

6 0

4 years ago

Can someone help with numbers 15 and 16

vichka [17]

15.

I had x before the movie.

x - 13.50 = 26.50

Add 13.50 to both sides of the equation:

x = 40

I had $40 before the movie.

16.

The original balance was x.

x - 161.15 = 423.28

Add 161.15 to both sides:

x = 584.43

The previous balance was $584.43

4 0

3 years ago

In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older

Viktor [21]

Answer:

$p_v =P(t_{(63)}>2.5)=0.0075$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=45$ represent the mean height for the sample

$s=16$ represent the sample standard deviation for the sample

$n=64$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:

Null hypothesis: $\mu \leq 40$

Alternative hypothesis: $\mu > 40$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=64-1=63$

Since is a one right tailed test the p value would be:

$p_v =P(t_{(63)}>2.5)=0.0075$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

6 0

3 years ago

!!help!!

IrinaVladis [17]

Answer:

3x

x

+

2

x

−

(5)(8)x

x

+2

=

−35x+2

x

Step-by-step explanation:

4 0

3 years ago

The greatest of the southern ocean

ycow [4]

Answer:

The Southern Ocean, also known as the Antarctic Ocean or the Austral Ocean, comprises the southernmost waters of the World Ocean, generally taken to be south of 60° S latitude and encircling Antarctica. As such, it is regarded as the second-smallest of the five principal oceanic divisions: smaller than the Pacific, Atlantic, and Indian Oceans but larger than the Arctic Ocean. This oceanic zone is where cold, northward flowing waters from the Antarctic mix with warmer subantarctic waters.

Step-by-step explanation:

5 0

3 years ago