Question

Solve for x in the equation 2 x squared + 3 x minus 7 = x squared + 5 x + 39.

Answer 1

Answer:

$\implies x=1\pm \sqrt{47}$

Step-by-step explanation:

We want to solve for x in $2x^2+3x-7=x^2+5x+39$

You need to group and combine like terms and write in standard form:

$2x^2-x^2+3x-5x-7-39=0$

$\imples x^2-2x-46=0$

By comparing to $ax^2+bx+c=0$, we a=1,b=-2 and c=-46

The solution can be obtained using the quadratic formula.

$x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

We substitute the coefficients to get:

$x=\frac{--2\pm \sqrt{(-2)^2-4*1*-46} }{2*1}$

$x=\frac{2\pm \sqrt{4+4*46} }{2}$

$x=\frac{2\pm \sqrt{4*47} }{2}$

$x=\frac{2\pm2\sqrt{47} }{2}$

$\implies x=1\pm \sqrt{47}$

The last choice is correct

Answer 2

Answer:

\implies x=1\pm \sqrt{47}

Step-by-step explanation: