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RSB [31]
3 years ago
10

PLEASE HELP I HAVE 3 MINS LEFT FAST!!!! ILL MARK BRAINLIEST!!!

Mathematics
1 answer:
GenaCL600 [577]3 years ago
7 0
A-1500
B-1500
C-1500+1500=3000
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Omg help me thissssss plsssss
igomit [66]

Answer:

3.5

Step-by-step explanation:

If you multiply 3.5 for example by 2 (which is the number of gallons) you get 7 which is the cost (also a proportional relationship).

4 0
3 years ago
F(x) = (x-3) (x+8) (x-11) <br> What are the zeros of the polynomial?
aalyn [17]
<span>hello :
</span>F(x) = (x-3) (x+8) (x-11)
F(x) =0
<span>x-3= 0 or x+8=0 or x-11 = 0
x=3 or x=-8 or x=11
</span><span>the zeros of the polynomialare : 3   , -8   , 11 </span><span>
</span>
6 0
3 years ago
Plz help me I really need it ASAP
vekshin1

Answer:

32

Step-by-step explanation:

\frac{4ab}{8c}

\frac{4(8)(4)}{8(\frac{1}{2})}

\frac{4(32)}{4}

32

8 0
2 years ago
Read 2 more answers
Determine the equation of the graph and select the correct answer below -2,-4
SVEN [57.7K]
Were is the rest of the question
5 0
3 years ago
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The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c
Anestetic [448]

Answer:

a) The mean is \mu = 60

b) The standard deviation is \sigma = 9

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when X = 55.5, Z = -0.5

So

Z = \frac{X - \mu}{\sigma}

-0.5 = \frac{55.5 - \mu}{\sigma}

-0.5\sigma = 55.5 - \mu

\mu = 55.5 + 0.5\sigma

The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.

This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when X = 71.52, Z = 1.28

So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{71.52 - \mu}{\sigma}

1.28\sigma = 71.52 - \mu

\mu = 71.52 - 1.28\sigma

Since we also have that \mu = 55.5 + 0.5\sigma

55.5 + 0.5\sigma = 71.52 - 1.28\sigma

1.78\sigma = 71.52 - 55.5

\sigma = \frac{(71.52 - 55.5)}{1.78}

\sigma = 9

\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60

Question

The mean is \mu = 60

The standard deviation is \sigma = 9

6 0
3 years ago
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