Question

What is the solution of the system?

Answer 1

Answer:

Option A is correct

$(-\frac{3}{2}, 4)$

Step-by-step explanation:

Given the system of equations:

$4x+3y = 6$                  ......[1]

$2x+2y = 5$                   .....[2]

Multiply equation [2]  by 2 to both sides we have;

$4x+4y = 10$                     ......[3]

Subtract [1] from [3] to eliminate x we have;

$4x+4y-4x-3y=10-6$

Combine like terms;

$y = 4$

Substitute this in [1] we have;

$4x+12 = 6$

Subtract 12 from both sides we have;

4x = -6

Divide both sides by 4 we get;

$x = -\frac{3}{2}$

therefore, the solution of the given system of equations is:

$(-\frac{3}{2}, 4)$

Answer 2

Answer: its A i took the test

Step-by-step explanation: