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vitfil [10]
3 years ago
10

To which family does the function y= (x+2)^1/2 +3 belong? A.quadratic B.square root C.exponential D.reciprocal

Mathematics
2 answers:
timofeeve [1]3 years ago
6 0

Answer:

B.square root

Step-by-step explanation:

Raising anything to the 1/2 power is the same as taking the square root of that term.

Since x would be under the square root sign (since it is part of the term being raised to the 1/2 power), this makes the function a square root function.

Alex Ar [27]3 years ago
5 0
It belongs to the square root family. Your answer is B. Why the square root family? Because y = (x+2)^{\frac{1}{2}} +3 can be written as y = \sqrt{(x+2)} + 3

When you raise to 1/2 or 1/3 it is like saying the square root or the cube root.
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Hey how do you get from standard form to vertex form?
vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be \mathbf{ax^{2}+bx+c=0} where x is the variable.

Completing the square method is as follows:

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  3. add \mathbf{(\frac{b}{2a})^{2}} to both side of equality                                   \mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}
  4. Make one fraction on the right side and compress the expression on the left side                                                                          \mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}
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Follow the above procedure will give the vertex form.

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8 0
3 years ago
What is?<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7By%7D%20%20%2B%20x" id="TexFormula1" title=" \frac{x}{y} + x"
Fiesta28 [93]

Answer:

\frac{x+xy}{y}

Step-by-step explanation:

Given

\frac{x}{y} + x

Multiply x by \frac{y}{y} to create a common denominator

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= \frac{x}{y} + \frac{xy}{y}

= \frac{x+xy}{y}

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