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Vanyuwa [196]
3 years ago
7

What is the value of x/2y , when x = 10 and y = 1? a. 1/10 b. 1/5 c. 5 d. 10

Mathematics
2 answers:
vivado [14]3 years ago
4 0

Answer: 5 is the answer to your question

Step-by-step explanation:

I took the K12 test and I hit review and that was the answer for your question.

butalik [34]3 years ago
3 0
X/2y = 10/2(1)
x/2y = 10/2
x/2y = 5

The answer is C.
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2 years ago
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

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b = BC = 12

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Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

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Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

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 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

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