It’s the sizes I’m pretty sure
Answer:
0
Step-by-step explanation:
Answer:
x=i√33−3,−i√33−3
hope this helps :)
Step-by-step explanation:
Subtract 5 from both sides of the equation.
(x+3)2=−28−
5 Subtract 5 from −28.
(x+3)2=−33
Take the square root of both sides of the equation to eliminate the exponent on the left side.
x+3=±√−33
Simplify the right side of the equation.
x+3=±i√33
The complete solution is the result of both the positive and negative portions of the solution.
x=i√33−3,− i√33 −3
Subtract sqrt(3) to both sides so that the equation becomes -3x^2 + 7x + 2 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [-b ± √(b^2 -4ac) ] / (2a)
x = [ -7 ± √((7)^2 - 4(-3)(2)) ] / ( 2(-3) )
x = [-7 ± √(49 - (-24) ) ] / ( -6 )
x = [-7 ± √(73) ] / ( -6)
x = [-7 ± sqrt(73) ] / ( -6 )
x = 7/6 ± -sqrt(73)/6
The answers are 7/6 + sqrt(73)/6 and 7/6 - sqrt(73)/6.
