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3 years ago

What is the constant rate of change of 4 in 7 days

Mathematics

1 answer:

Genrish500 [490]3 years ago

5 0

Well I think it's 1.75 I think I could be wrong

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Josh borrowed $50,000 from the bank to buy a new truck. The bank is going to charge him an interest rate of 6.9%. If his loan la

Neko [114]

Answer:

The simple interest is $11,212.5 and the equation to determine Josh's simple interest is I = PRT/100

Step-by-step explanation:

The formula for calculating simple interest is expressed as;

SI = Principal * rate * time/100

SI = 50,000 * 6.9*39/100*12

SI = 500*6.9*39/12

SI = 134,550/12

SI = 11,212.5

Hence the simple interest is $11,212.5 and the equation to determine Josh's simple interest is I = PRT/100

P is the amount borrowed

R is the interest rate

T is the time in years

8 0

2 years ago

Solve for m: 2r= m/r m = 2r m = 2r squared by 2 m=r m = 2

Bad White [126]

Solution

Switch sides so that m is on the left side

m/r = 2r

Them multiply both sides by r

mr/r = 2rr

Now simplify the equation

m = 2r^2

Therefore the equation evaluates to
m = 2r squared by 2

6 0

2 years ago

56:12

Gre4nikov [31]

Answer:

The official answer is {C} ive previously taken the test

Step-by-step explanation:

I have taken the test before hand.

5 0

2 years ago

Hi hello yes can someone help me out?

abruzzese [7]

Answer:

a c and d

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

5 0

3 years ago