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katen-ka-za [31]
3 years ago
12

What is the slope of the line that passes through the point 3,5 and -2,2

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

3/5

Step-by-step explanation:

Slope=

\frac{y2 - y1}{x2 - x1}

slope =

\frac{2 - 5}{ - 2 - 3}

=

\frac{3}{5}

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How to find the opposite side of a triangle?
aivan3 [116]

Answer:

Pythagoros Therom

Step-by-step explanation:

The pythagoros therom  will help you find any side of a triangle as long as you already know 2 of the sides the equation is a^2+b^2=c^2 and c is the hypotenuse(the longest leg) and a and b are the other two legs. You might wanna learn this thouroghly but it is very easy to learn trust me.

6 0
2 years ago
100e^0.125t=200<br><br>A. t= ln(16)<br>B. t= ln(256)<br>C. t= 8ln(100)<br>D. t= 0.08ln(200)
Drupady [299]

The correct answer is C. t= 8ln(100)

Hope this helped! :)



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5 0
3 years ago
You have 60.00 in your wallet and you want to buy some new cds. if the cd's are 11.00 each, what number of cd's x can you buy?wr
Dvinal [7]
You have $60.00.
Each CD (x) is $11.00.

11x ≤ 60
The number of CDs multiplied by the cost (11) has to be less than or equal to 60. 
x ≤ 5.45

You can only buy 5 CDs.
3 0
3 years ago
You are doing marketing research to find out the purchasing potential of students in the community. Based on the latest census,
Angelina_Jolie [31]
Number of students = 9860
Total Population = 62,400

Percentage of students in the population can be calculated by:

(Number of students/Total population) x 100%

Using the values, we get:

Percentage of students = (9860/62400) x 100% = 15.80%

Thus, students constitute 15.80% of the entire population
6 0
2 years ago
Read 2 more answers
Solve |3k-2|=2|k+12|
Stella [2.4K]

Answer:

k = 26   or   k = -\dfrac{22}{5}

Step-by-step explanation:

|3k - 2| = 2|k + 12|

\dfrac{|3k - 2|}{|k + 12|} = 2

|\dfrac{3k - 2}{k + 12}| = 2

3k - 2 = 2(k + 12)   or   3k - 2 = -2(k + 12)

3k - 2 = 2k + 24   or   3k - 2 = -2k - 24

k = 26   or   5k = -22

k = 26   or   k = -\dfrac{22}{5}

7 0
3 years ago
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