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3 years ago

14

The percentage change of a ratio of two variables is approximately the percentage change in the numerator _____ the percentage c

hange in the denominator.

2 answers:

olchik [2.2K]3 years ago

8 0

Answer:

"The percentage change of a ratio of two variables is approximately the percentage change in the numerator <u>minus</u> the percentage change in the denominator."

Step-by-step explanation:

The percent change in a number is determined by dividing the difference between the new number and original number by the original number and multiplying the result by 100.

Suppose the original ratio of two numbers is: $\frac{25}{100}$ .

And the new ratio is: $\frac{75}{100}$

The percent change is:

$Change\%=\frac{75-25}{100}\times100=\frac{50}{100}\times100=50\%$

Thus, the complete statement is:

"The percentage change of a ratio of two variables is approximately the percentage change in the numerator <u>minus</u> the percentage change in the denominator."

s344n2d4d5 [400]3 years ago

6 0

Answer: MINUS

Step-by-step explanation:

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san4es73 [151]

Answer:

y = -2x + 9

Step-by-step explanation:

y = -2x + 7

(4, 1)

1 = -2 ( 4 ) + b

1 = -8 + b

b = 9

y = -2x + 9

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3 years ago

Factorizar A- m⁹+125<br>B - 125a³ + 150a² b + 60ab³ + 8b³

UkoKoshka [18]

Answer:

Kya Hua Hai Bhai Sab Kuchh khae Duniya Mein Sab Koi pata nahin to Aap To Pyar Karte

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3 years ago

10 points!!! please help :(

daser333 [38]

To complete the identity, we need these fundamental identities:

$1)\displaystyle{sec(x)=\frac{1}{cos(x)}$

$2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)$

$\displaystyle{csc(x)= \frac{1}{sin(x)}$

Thus, by identity 1 we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}$

by identity :

$\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)$

recall the values :

$\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\$

$\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0$ ,

so:

$cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)$

Putting all these together, we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}$

which is equal to $csc(\theta)$ , by identity 3

Answer: D

7 0

3 years ago

Suppose the population of a certain city is 3031 thousand. It is expected to decrease to 2246 thousand in 50 years. Find the per

Kipish [7]

Answer:

The rate at which the population decrease is 59.8 %

Step-by-step explanation:

Given as :

The population of city = 30,31,000

Now The population of city decrease to 22,46,000

The time period in which population decrease is 50 years

Let the percentage rate of decrease = R%

So,

Final population = initial population × $(1-\frac{Rate}{100})^{Time}$

Or, 22,46,000 = 30,31,000 × $(1-\frac{Rate}{100})^{50}$

Or, $\frac{2246000}{3031000}$ = $(1-\frac{Rate}{100})^{50}$

Or, $\frac{2246}{3031}$ = $(1-\frac{Rate}{100})^{50}$

$(\frac{2246}{3031})^{\frac{1}{50}}$ = $( 1-\frac{Rate}{100})$

So , 0.99402 = $( 1-\frac{Rate}{100})$

Or, $\frac{Rate}{100}$ = 1 - 0.99402

So, Rate = $5.98\times 10^{-3}$ × 100

Or, Rate = 0.598 = 59.8 %

Hence The rate at which the population decrease is 59.8 % Answer

4 0

3 years ago

Which shows two expressions that are equivalent to (-7)(-15)(-5)?

shusha [124]

B is the correct answer

C and D would be incorrect as 7 and 15 multiplies to 105 not 115
A is incorrect as -5 and -15 make a positive 75 not a negative 75

8 0

3 years ago